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3 years ago

A planet orbiting the Sun will experience the largest gravitational force and greatest tangential speed when it is

Chemistry

1 answer:

Travka [436]3 years ago

8 0

Answer:

A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves. The farther it is from the Sun, the weaker the Sun's gravitational pull, and the slower it moves in its orbit.

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The needles of an evergreen tree are most similar to what part of other trees?

tatuchka [14]

Answer:

the leaves i think

Explanation:

i had this on a test once.

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3 years ago

An atom of boron has an atomic number of 5 and an atomic mass of 11. The atom contains

Liono4ka [1.6K]

Answer:

5 protons, 5 electrons, and 6 neutrons

3 0

3 years ago

Which of the following would you expect to have

IRISSAK [1]

Explanation:

number b is the answer for the question

6 0

3 years ago

The heat of vaporization for liquid zinc is 1.76 kj/g. How much heat is needed to boil 11.2 g of liquid zinc already at its boil

sladkih [1.3K]

<h3>Answer:</h3>

= 19.712 kJoules

<h3>Explanation:</h3>

Heat of vaporization refers to the amount of heat required to change a unit mass of a substance from liquid to gaseous state without change in temperature.

To calculate the amount of heat, we use,

Amount of heat = Mass × Heat of vaporization

Q = m×Lv

Given;

Mass of liquid Zinc = 11.2 g

Lv of liquid Zinc = 1.76 kJ/g

Therefore;

Q = 11.2 g × 1.76 kJ/g

= 19.712 kJ

Thus, the amount of heat needed to boil 11.2 g of zinc is 19.712 kilo-joules.

6 0

3 years ago

Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.850 atm

alekssr [168]

Answer:

(I). The gases are present at the end of the experiment are O₂ and NO₂

(II). The pressure of O₂ is 0.158 atm.

The pressure of NO₂ is 0.681 atm

The Pressure of NO is zero.

Explanation:

Given that,

Volume of large bulb = 6.00 L

Pressure = 0.850 atm

Volume of small bulb = 1.50 L

Pressure = 2.50 atm

Temperature = 22°C = 295 K

We need to calculate the moles in NO

Using formula of moles

$n=\dfrac{PV}{RT}$

Put the value into the formula

$n=\dfrac{0.850\times6.00}{0.0821\times295}$

$n=0.211\ moles$

We need to calculate the moles in O

Using formula of moles

$n=\dfrac{PV}{RT}$

Put the value into the formula

$n=\dfrac{2.50\times1.50}{0.0821\times295}$

$n=0.155\ moles$

The balance equation for the reaction is

$2NO+O_{2}\Rightarrow 2NO_{2}$

So, The gases are present at the end of the experiment are O₂ and NO₂

We need to calculate the remaining moles of O₂

Using formula for remaining moles

Moles of O₂ remaining = $0.155-\dfrac{0.211}{2}$

$Moles\ of \ O_{2}\ remaining =0.049\ moles$

Moles of NO₂ = 0.211 moles

Total volume $V=V_{l}+V_{s}$

Put the value into the formula

$V=6.00+1.50$

$V=7.5\ V$

(2). If the gas was consumed completely

We need to calculate the pressure of O₂

Using formula of pressure

$P=\dfrac{moles\times R\times T}{V}$

Put the value into the formula

$P=\dfrac{0.049\times0.0821\times295}{7.5}$

$P=0.158\ atm$

We need to calculate the pressure of NO₂

Using formula of pressure

$P=\dfrac{moles\times R\times T}{V}$

Put the value into the formula

$P=\dfrac{0.211\times0.0821\times295}{7.5}$

$P=0.681\ atm$

If the gas was consumed completely

Then, Pressure of NO is zero.

Hence, (I). The gases are present at the end of the experiment are O₂ and NO₂

(II). The pressure of O₂ is 0.158 atm.

The pressure of NO₂ is 0.681 atm

The Pressure of NO is zero.

8 0

3 years ago