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motikmotik
3 years ago
15

I need help ASAP 10 points

Chemistry
1 answer:
jekas [21]3 years ago
4 0

Answer:

the sun beams down on the pool and heats it up top to bottom the deeper the colder

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Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
LenaWriter [7]

Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

\Delta T_f=i\times k_f\times m..[1]

m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}

Where:

i = van't Hoff factor

k_f = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: \Delta T_{f,A}

Molar mass of A = M_A

The depression in freezing point of solution with B solute: \Delta T_{f,B}

Molar mass of B = M_B

\Delta T_{f,A}>\Delta T_{f,B}

As we can see in [1] , that depression in freezing point is inversely related to molar mass of the solute.

\Delta T_f\propto \frac{1}{\text{Molar mass of solute}}

M_A

This means compound B has greater molar mass than compound A,

4 0
3 years ago
A rectangular field measures 6.0 m by 8.0 m. What is the area of the field in square centimeters (cm 2 )? Use the formula: Area
Lera25 [3.4K]
The answer is C

6.0m x 8.0m= 48.0m

then converting it to cm by multiply
48 x 100
7 0
3 years ago
At a given temperature the vapor pressures of hexane and octane are 183 mmhg and 59.2 mmhg, respectively. Calculate the total va
Bas_tet [7]

Total vapor pressure can be calculated using partial vapor pressures and mole fraction as follows:

P=X_{A}P_{A}+X_{B}P_{B}

Here, X_{A} is mole fraction of A, X_{B} is mole fraction of B, P_{A} is partial pressure of A and P_{B} is partial pressure of B.

The mole fraction of A and B are related to each other as follows:

X_{A}+X_{B}=1

In this problem, A is hexane and B is octane, mole fraction of hexane is given 0.580 thus, mole fraction of octane can be calculated as follows:

X_{octane}=1-X_{hexane}=1-0.58=0.42

Partial pressure of hexane and octane is given 183 mmHg and 59.2 mmHg respectively.

Now, vapor pressure can be calculated as follows:

P=X_{hexane}P_{hexane}+X_{octane}P_{octane}

Putting the values,

P=(0.580)(183 mmHg)+(0.420)(59.2 mmHg)=131 mmHg

Therefore, total vapor pressure over the solution of hexane and octane is 131 mmHg.

4 0
3 years ago
How many protons are in 10 moles of gold? Please help! Thank you!
irinina [24]
3 is the answer hope it helps
3 0
3 years ago
Read 2 more answers
Is this correct please help?
iren [92.7K]

Answer:

\boxed {\tt Number \ and \ unit}

Explanation:

The two requirements for a measurement are a <u>number</u> and a <u>unit.</u>

For example, here is a measurement:

38.6 cm

The <u>number</u> is 38.6 and the <u>unit</u> is cm, or centimeters.

Therefore, both <em>number </em>and <em>unit</em> are correct.

7 0
3 years ago
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