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3 years ago

When might a large volume of material have little mass?

1 answer:

5 0

For a solid I would say something like aerogel would have a large volume but very little mass.

Let me know if this helped or not.

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What is the correct formula for xenon hexafluoride

LiRa [457]

Formula for Xenon hexafluoride is XeF6

4 0

3 years ago

Read 2 more answers

1. The solubility of AgNO3 at 20°C is 222.0g AgNO3/100g H2O. What mass of AgNO3 can be dissolved in 250 g of water at 20°C? Reca

neonofarm [45]

Answer :

(1) The mass of silver nitrate is, 555 g

(2) The solubility of the gas will be, 0.433 g/L

Solution for Part 1 :

From the given data we conclude that

In 100 gram of water, the amount of silver nitrate = 222 g

In 250 gram of water, the amount of silver nitrate = $\frac{222}{100}\times 250=555g$

Therefore, the mass of silver nitrate is, 555 g

Solution for Part 2 :

Formula used : $S_1P_1=S_2P_2$ (at constant temperature)

where,

$S_1$ = initial solubility of methane gas = 0.026 g/L

$S_2$ = final solubility of methane gas

$P_1$ = initial pressure of methane gas = 1 atm

$P_2$ = final pressure of methane gas = 0.06 atm

Now put all the given values in the above formula, we get the solubility of methane gas.

$(0.026g/L)\times (1atm)=S_2\times (0.06atm)$

$S_2=0.433g/L$

Therefore, the solubility of the gas will be, 0.433 g/L

5 0

3 years ago

A store sell 21 piece of clothing every 45 minutes.How long will it take the store to sell 100 pieces of clothing?

zmey [24]

Explanation:

21 piece =45 mins

100 pieces= x

on cross multiplication

21x=45×100mins

21x =4500mins

x =4500mins÷21

 =214.3mins or 3.57hrs

3 0

2 years ago

I will give brainliest!!! In the reaction represented by the equation Al2O3 -> Al + O2, what is the mole ratio of aluminum to

Effectus [21]

Answer:;

4:3

Explanation:

Balanced:

4Al + 302 yields 2al2O3

7 0

3 years ago

In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t

solmaris [256]

Answer:

4.81 moles

Explanation:

The total pressure of the gas = Pressure at which gauge reads zero + pressure read by it.

Pressure at which gauge reads zero = 14.7 psi

Pressure read by the gauge = 988 psi

Total pressure = 14.7 + 988 psi = 1002.7 psi

Also, P (psi) = P (atm) / 14.696

Pressure = 1002.7 / 14.696 = 68.2297 atm

Temperature = 25 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (25 + 273.15) K = 298.15 K

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

68.2297 atm × 1.5 L = n × 0.0821 L.atm/K.mol × 298.15 K

⇒n = 4.81 moles

4 0

3 years ago