Question

A box is partially filled with liquid. The length of the box is 18 inches. The width of the box is 12 inches. If the volume of the liquid is increasing at a rate of 569 cubic inches per second, what is the rate, in inches per second, at which the height of the liquid is changing when the height of the liquid is 4 inches?

Answer 1

Answer:2.634 in./s

Step-by-step explanation:

Given

Length (L)=18 in.

width (B)=12 in.

height(h)=4 in.

Volume of water is increasing at a rate of 569 $in^3/s$

Volume of a box is given by=LBh

and $\dot{V}=LB\dot{h}$

as L&B are constant therefore

$\dot{V}=18\times 12\times \dot{h}$

$\dot{h}=2.634 in./s$