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padilas [110]
3 years ago
9

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

e given equation. Using the equation, what height was the rocket launched from? y=-16x^2+57x+32
Mathematics
1 answer:
iren [92.7K]3 years ago
6 0

9514 1404 393

Answer:

  32 feet

Step-by-step explanation:

0 seconds after launch, the rocket is still sitting on the tower. Its height is...

  y = -16(0^2) +57(0) +32

  y = 0 + 0 + 32 = 32

The rocket was launched from a tower 32 feet high.

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ASSAP EASY MATH does a shape stay congruent when it has been rotated
Romashka-Z-Leto [24]

Answer:

They are still congruent even after being rotated they still will remain the same shape.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
which statement correctly descibes what happens to the shape and location of the graph of y=2x^2 if it is regraphed as y=-1/2x^2
lbvjy [14]
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4 0
3 years ago
One angle measures nine more than six times a number. A sequence of rigid motions maps the angle onto another angle that describ
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Answer:

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3 0
4 years ago
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Answer:

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3 years ago
1) Easton went to a concert with some
tatuchka [14]
Subtract the 15 from the 133
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4 people went to the concert
7 0
3 years ago
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