A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

Question

3 years ago

9

e given equation. Using the equation, what height was the rocket launched from? y=-16x^2+57x+32

1 answer:

iren [92.7K] · Answer 1 · 2022-07-31T22:00:53+03:00

6 0

9514 1404 393

Answer:

32 feet

Step-by-step explanation:

0 seconds after launch, the rocket is still sitting on the tower. Its height is...

y = -16(0^2) +57(0) +32

y = 0 + 0 + 32 = 32

The rocket was launched from a tower 32 feet high.