Which of the following is a solution of x2 + 4x = −8?

1 answer:

6 0

$x^{2}+4x = -8
\\\\
x^{2}+4x+8 = 0
\\\\
\Delta = b^{2}-4ac
\\\\
\Delta = (4)^{2}-4 \cdot (1) \cdot (8)
\\\\
\Delta = 16-32
\\\\
\Delta = -16$

There's no solution in the set of real numbers.

$\boxed{S = \{ \ \ \}}$

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