Question

If a 10,000 g mass is suspended from a rope, what is the tensile force in the rope?

Answer 1

To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function

$F = ma\rightarrow F =mg$

Here,

m = mass

a = g = Gravitational acceleration

Replacing we have that the weight is

$W= (10kg)(9.8)$

$W = 98N$

Since the rope is taut and does not break, the net force on the rope will be zero.

$\sum F = 0$

$T-W = 0$

$T = W$

$T = 98N$

Therefore the tensile force in the rope is 98N