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2 years ago

If a 10,000 g mass is suspended from a rope, what is the tensile force in the rope?

1 answer:

8 0

To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function

$F = ma\rightarrow F =mg$

Here,

m = mass

a = g = Gravitational acceleration

Replacing we have that the weight is

$W= (10kg)(9.8)$

$W = 98N$

Since the rope is taut and does not break, the net force on the rope will be zero.

$\sum F = 0$

$T-W = 0$

$T = W$

$T = 98N$

Therefore the tensile force in the rope is 98N

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Write a list of at least five scientific methods.

kolbaska11 [484]

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5- Record observations and analyze what the data means.
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3 years ago

In the table below,which statement would best fill the missing box under isolated systems?

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Answer:

b-energy is not exchanged

Explanation:

An isolated system is a thermodynamic system in which neither energy nor matter is exchanged with the surroundings.

As such the best statement that will fill the box under an isolated system is that energy is not exchanged.

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2 years ago

Which type of reaction does this chemical equation represent? 2Na + MgCl2 - 2NaCl + Mg

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2 years ago

Read 2 more answers

A soccer ball is kicked and left the ground at angle 45° above the horizantal, moving at 25 m/s.

Tcecarenko [31]

Answer:

a) 3.6 sec

b) 17.7 m/s

c) 17.7 m/s

d) 63.6 m

Explanation:

y = (25sin45)t - 4.9t^2 =17.7t - 4.9t^2

a) to find hang time set y = 0

4.9t^2 = 17.7t or t = 3.6 sec

b) vx = 25cos45 = 17.7 m/s

c) vy = 25sin45 = 17.7 m/s

d) To find the range R, use the results in (a) and (b) into the equation R = vxt:

R = (17.7 m/s)(3.6 sec) = 63.6 m

8 0

3 years ago

A tellurium-sapphire laser can produce light at wavelength of 800 nm in ultrashort pulses that last only 4.00x10-15s (4.00 femto

natka813 [3]

The speed of light and the propagation of errors allows to find the results on the questions of the radiation emitted by the laser are:

a) The frequency is: f = 3.7 10¹⁴ Hz

b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

a) The speed of a wave is related to its wavelength and frequency.

c = λ f

$f = \frac{c}{\lambda}$

Where c is the speed of light, λ the wavelength and f the frequency.

They indicate that the wavelength is λ = 800 nm = 800 10⁻⁹ m, the speed of light is a constant c = 2.99 10⁸ m/s.

f = $\frac{2.99 \ 10^8}{800 \ 10^{-9}}$

F = 3.7 10¹⁴ Hz

b) Planck's equation states that the energy is proportional to the frequency of the radiation.

E = h f

Where E is the energy, h the Planck constant and f the frequency.

E = 6.63 10⁻³⁴ 3.7 10¹⁴

E = 2.46467 10⁻¹⁹ J

The uncertainty or error is the fluctuation that a magnitude may have due to the precision in the measurements, when the magnitude is calculated by some formula, the propagation of these uncertainties must be carried out.

Δm = ∑ $\sum \frac{dm}{dx_i} | \Delta x_I|$

the expression for energy is:

E = $\frac{hc}{\lambda }$

$\Delta E = \frac{dE}{d \lambda} |D\lambda |$

$\Delta E = \frac{h c }{\lambda^2 } |\Delta \lambda |$

When the error in the measured magnitude is not explicitly indicated, we assume that the error is in the last digit written, therefore

Δλ = ± 1 nm = ± 1 10⁻⁹ m

We calculate.

$\Delta E = \frac{6.63 \ 10^{-34} \ 2.99 \ 10^8 }{(800 \ 10^{-9})^2} 1 \ 10^{-9}$

ΔE = 3.1 10⁻²² J

the error is given with a significant figure.

ΔE = 3 10⁻²² J = 0.004 10⁻¹⁹ J

The result of the energy is:

E = (2.465 ± 0.004) 10⁻¹⁹ J

In conclusion, using the speed of light and the propagation of errors, we can find the results on the questions of the radiation emitted by the laser are:

a) The frequency is; f = 3.7 1014 Hz

b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

Learn more here: brainly.com/question/15557220

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2 years ago