If a 10,000 g mass is suspended from a rope, what is the tensile force in the rope?
1 answer:
To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function
Here,
m = mass
a = g = Gravitational acceleration
Replacing we have that the weight is
Since the rope is taut and does not break, the net force on the rope will be zero.
Therefore the tensile force in the rope is 98N
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Answer:
Both objects have the same magnitude of momentum.
Explanation:
If an object of mass is moving at a velocity of
, the momentum of that object would be
.
The (
) object is moving at a speed of
. The magnitude of the momentum of this object would be
.
Similarly, the momentum of the (
) object moving at a speed of
would be
.
Hence, the magnitude of momentum is the same for the two objects.
The question is incomplete. The mass of the object is 10 gram and travelling at a speed of 2 m/s.
Solution:
It is given that mass of object before explosion is,m = 10 g
Speed of object before explosion, v = 2 m/s
Let be the masses of the three fragments.
Let be the velocities of the three fragments.
Therefore, according to the law of conservation of momentum,
So the x- component of the velocity of the m2 fragment after the explosion is,
∴