Answer: 0.1125A
Explanation:
We need to know the total resistance which will be:
R = R1+R2
where,
R1 = 20 ohm
R2 = 60 ohm
Therefore, R = 20 + 60 = 80 ohm
We should note that from Ohm's law
v = iR
i = v/R
where,
i = 9/80 = 0.1125 A
Therefore, the current that flows out of the battery is 0.1125A
Answer:
The electric force on q₁ is
.
Explanation:
Given that,
Charge on ![q_{1}=-6.0\ \mu C](https://tex.z-dn.net/?f=q_%7B1%7D%3D-6.0%5C%20%5Cmu%20C)
Distance ![x= -3.0\ m](https://tex.z-dn.net/?f=x%3D%20-3.0%5C%20m)
Charge on
at origin
Distance ![x= 3.0\ m](https://tex.z-dn.net/?f=x%3D%203.0%5C%20m)
Charge on ![q_{3}=-1.0\ \mu C](https://tex.z-dn.net/?f=q_%7B3%7D%3D-1.0%5C%20%5Cmu%20C)
We need to calculate the electric force on q₁
Using formula of electric force
![F_{12}=\dfrac{kq_{1}q_{2}}{r^2}](https://tex.z-dn.net/?f=F_%7B12%7D%3D%5Cdfrac%7Bkq_%7B1%7Dq_%7B2%7D%7D%7Br%5E2%7D)
Put the value into the formula
![F_{12}=\dfrac{9\times10^{9}\times(-6.0\times10^{-6})\times1.0\times10^{-6}}{(3.0)^2}](https://tex.z-dn.net/?f=F_%7B12%7D%3D%5Cdfrac%7B9%5Ctimes10%5E%7B9%7D%5Ctimes%28-6.0%5Ctimes10%5E%7B-6%7D%29%5Ctimes1.0%5Ctimes10%5E%7B-6%7D%7D%7B%283.0%29%5E2%7D)
![F_{12}=-0.006\ N](https://tex.z-dn.net/?f=F_%7B12%7D%3D-0.006%5C%20N)
Negative sign shows the attraction force.
We need to calculate the electric force F₁₃
![F_{13}=\dfrac{9\times10^{9}\times(-6.0\times10^{-6})\times(-1.0\times10^{-6})}{(6.0)^2}](https://tex.z-dn.net/?f=F_%7B13%7D%3D%5Cdfrac%7B9%5Ctimes10%5E%7B9%7D%5Ctimes%28-6.0%5Ctimes10%5E%7B-6%7D%29%5Ctimes%28-1.0%5Ctimes10%5E%7B-6%7D%29%7D%7B%286.0%29%5E2%7D)
![F_{13}=0.0015\ N](https://tex.z-dn.net/?f=F_%7B13%7D%3D0.0015%5C%20N)
Positive sign shows the repulsive force.
We need to calculate the net electric force
![F=F_{12}+F_{13}](https://tex.z-dn.net/?f=F%3DF_%7B12%7D%2BF_%7B13%7D)
![F=-0.006+0.0015](https://tex.z-dn.net/?f=F%3D-0.006%2B0.0015)
![F=0.0045\ N](https://tex.z-dn.net/?f=F%3D0.0045%5C%20N)
![F=4.5\times10^{-3}\ N](https://tex.z-dn.net/?f=F%3D4.5%5Ctimes10%5E%7B-3%7D%5C%20N)
Hence, The electric force on q₁ is
.
Answer:
M = 1.38 10⁵⁹ kg
Explanation:
For this problem we will use the law of universal gravitation
F = G m₁ m₂ / r²
Where G is the gravitation constant you are value 6.67 10⁻¹¹ N m2 / kg2, m are the masses and r the distance
In this case the mass of the planet is m = 3.0 10²³ kg and the mass of the start is M
Let's write Newton's second law
F = m a
The acceleration is centripetal
a = v² / r
The speed module is constant, so we can use the kinematic relationship
v = d / t
The distance remembered is the length of the circular orbit and the time in this case is called the period
d = 2π r
a = 2π r / T
Let's replace Newton's second law
G m M / r² = m (4π² r² / T²) / r
G M = 4 π² r³ / T²
M = 4 π² r³ / T² G
Let's calculate
M = 4 π² (3.0 10²³)³ / (3.4 10¹¹)² 6.67 10⁻¹¹
M = 13.82 10⁵⁸ kg
M = 1.38 10⁵⁹ kg
Answer:
Explanation:
length of the wire = L
Potential difference = Vo
Current = I
new length of the wire, L' = L/2
As we know that the resistance of the wire is directly proportional to the length of the wire.
As the length is halved so that the resistance is also halved.
Resistance = Voltage / Current
V = I R
So, Voltage is constant and the resistance is halved so that the current is doubled.
The electrostatic force between the two charges is ![3.4\cdot 10^{-8}N](https://tex.z-dn.net/?f=3.4%5Ccdot%2010%5E%7B-8%7DN)
Explanation:
The electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, we have the following data:
is the magnitude of the two charges, where
is the fundamental charge
is the separation between the two charges
Substutiting into the equation, we find the force:
![F=(8.99\cdot 10^9)\frac{(1.00\cdot 1.6\cdot 10^{-19})^2}{(8.19\cdot 10^{-11})^2}=3.4\cdot 10^{-8}N](https://tex.z-dn.net/?f=F%3D%288.99%5Ccdot%2010%5E9%29%5Cfrac%7B%281.00%5Ccdot%201.6%5Ccdot%2010%5E%7B-19%7D%29%5E2%7D%7B%288.19%5Ccdot%2010%5E%7B-11%7D%29%5E2%7D%3D3.4%5Ccdot%2010%5E%7B-8%7DN)
Learn more about electric force:
brainly.com/question/8960054
brainly.com/question/4273177
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