Answer:
The larger pebble has 25 times more mass.
Explanation:
To solve the exercise it is necessary to apply the work and energy conservation equations.
For the case described, the work done must be preserved and must be the same, that is,
By definition work linked to the conservation of kinetic energy would be given by
The ratio between the mass and the velocity would be,
Therefore the answer is: The larger pebble has 25 times more mass.
<h2>
She will find the ball at a horizontal distance of 86.4 m from landed location</h2>
Explanation:
Consider the vertical motion of ball
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 2 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 100 m
Substituting
s = ut + 0.5 at²
100 = 2 x t + 0.5 x 9.81 xt²
4.905t² + 2t - 100 = 0
t = 4.32 s or t = -4.72 s
After 4.32 seconds the ball reaches ground.
Now we need to find horizontal distance traveled by ball in 4.32 seconds.
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 20 m/s
Acceleration, a = 0 m/s²
Time, t = 4.32 s
Substituting
s = ut + 0.5 at²
s = 20 x 4.32 + 0.5 x 0 x 4.32²
s = 86.4 m
She will find the ball at a horizontal distance of 86.4 m from landed location
Answer:
ok so youll tell me when you have problems
Answer:
14 cm
Explanation:
Power of eye = 57.1 D
The relation between the focal length and the power is
f = 1 / P = 1 / 57.1 = 0.0175 m = 1.75 cm
The distance between the image and the lens is, v = 2 cm
Let the distance between the object and the eye is u
Use the lens equation
1/ f = 1 / v - 1 / u
1 / 1.75 = 1 / 2 - 1 / u
1 / u = 1 / 2 - 1 / 1.75
1 / u = (1.75 - 2) / 3.5
u = - 14 cm
Thus, the distance between the feature and eye is 14 cm .
Well they live in dry areas bc there jumps hole water
