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Evgesh-ka [11]
2 years ago
15

How to factorise 9a^2bc^3 -27abc

Mathematics
1 answer:
olga2289 [7]2 years ago
3 0

Answer:

9abc(ac² - 3)

Step-by-step explanation:

<u>Given polynomial:</u>

  • 9a²bc³ -27abc

<u>Factors of the terms:</u>

  • 9a²bc³ = 3*3*a*a*b*c*c*c
  • 27abc = 3*3*3*a*b*c

<u>Common factors of the above: </u>

  • 3*3*a*b*c= 9abc

<u>So the answer:</u>

  • 9a²bc³ -27abc = 9abc(ac² - 3)
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This is what I've done so far but does anyone know what I do next or did I make a mistake
grigory [225]
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