Question

How to factorise 9a^2bc^3 -27abc

Answer 1

Answer:

9abc(ac² - 3)

Step-by-step explanation:

Given polynomial:

• 9a²bc³ -27abc

Factors of the terms:

• 9a²bc³ = 3*3*a*a*b*c*c*c
• 27abc = 3*3*3*a*b*c

Common factors of the above:

• 3*3*a*b*c= 9abc

So the answer:

• 9a²bc³ -27abc = 9abc(ac² - 3)