How to factorise 9a^2bc^3 -27abc

Mathematics

1 answer:

olga2289 [7]3 years ago

3 0

Answer:

9abc(ac² - 3)

Step-by-step explanation:

Given polynomial:

9a²bc³ -27abc

Factors of the terms:

9a²bc³ = 3*3*a*a*b*c*c*c
27abc = 3*3*3*a*b*c

Common factors of the above:

3*3*a*b*c= 9abc

So the answer:

9a²bc³ -27abc = 9abc(ac² - 3)

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