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3 years ago

13

Solve the following absolute value inequality, 2/2x-1| +4 < 10

1 answer:

DENIUS [597]3 years ago

7 0

Answer:

x<2

Step-by-step explanation:

First you would subtract 4 from both sides to get 2|2x-1|<6

Then you would divide by 2 to get 2x-1<3

next you would add 1 on both sides to get 2x<4

Finally divide by 2 to get x<2

Hope this helped please give brainliest

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3 years ago

What is the distance between 5,4 and -1,1

spayn [35]

Answer:

3 $\sqrt{5}$

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

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3 years ago

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2 years ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Read more about hyperbolas at:

brainly.com/question/15697124

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3 years ago

Read 2 more answers

Convert each function to standard form<br>31) y=(x + 2)2 + 1

vlada-n [284]

The standard form of a parabola is

$y=ax^2+bx+c$

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$y=(x+2)^2+1 = x^2+4x+4+1 = x^2+4x+5$

which is the standard form

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3 years ago