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sesenic [268]
4 years ago
14

Identify the root folder in the absolute path /folder1/folder2/folder3/file.

Computers and Technology
2 answers:
WINSTONCH [101]4 years ago
8 0

Answer:

The folder 1 is the root folder followed by all other sub-folders, which is absolute path/folder1/folder2/folder3/file

Explanation:

<em>From the given question , we find the root folder</em>

<em>Root folder</em><em>: it can be defined as the folder that is at the top of  all hierarchy, folders comprising of all other folders</em>

<em>A path that begins from the root folder and moves down the entire folder structure is given as this  path/folder1/folder2/folder3/file </em>

<em>Therefore the absolute path starts from the root folder,</em>

<em>where folder1 is the root folder, followed by the sub-folders</em>

Lilit [14]4 years ago
3 0
Absolute path always start from the root folder.
folder 1 /folder 2 / folder 3 / file.
Here the path start from folder 1, which is the root folder.
Folder 2 and folder 3 are the sub-folders.



Answer: Folder 1
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2 years ago
a program p takes time proportional to log where nlogn is the input size. if the program takes 100 ms to process input of size 1
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Answer:

The time is 4 \times 10^7 \ microseconds.

Explanation:

\ The \ requires \ time \ be \ t \ microseconds, \\\\\ \ formula: \\\\ time \propto \ nlog_n \Rightarrow \ time \ = \ knlogn \\\\

\ 10 \ = \ 100 \ log(100) \ \ \ \ \ \ \ \ \ k= 10^2 \ log\ ( \ 10^2\ ) \ k\\\\t=100,000,000 \log \ ( \ 100,000,000\ ) \ k = \ 10^8 \ log\ (\ 10^8\ )\ k \\\\\rightarrow \frac{t}{10} \ =\frac{10^8\ log \ (10^8)k}{10^2\ log\(10^2\ ) k} \\\\\rightarrow \frac{t}{10} \ =\frac{10^8\ log \ (10)\times 8 \times k}{10^2\ log\(10) \times 2 k} \\\\\rightarrow \frac{t}{10} \ =\ 4\times 10^6\\\\\rightarrow \ t \ =\ 4\times 10^6 \times 10 \\\\\rightarrow \ t \ =\ 4\times 10^7 \ microseconds \\\\

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4 years ago
Which Creative Commons license type allows others to use and build upon work non-commercially, provided that they credit origina
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Answer:

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Attribution-Non financially-ShareAlike

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Solution :

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   }

   return isPalindrome

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