Answer:
a. 0.01
b. 0.001
c. The identification field of the packet fragment can be used to uniquely identify and collate the fragments lost in transmission.
Explanation:
The probability of losing a packet is 10% or 0.1, so the probability of losing the packet twice during transmission;
= 0.1 x 0.1 = 0.01
When any fragments have been part of the transmission, the probability of the packet is dependent on the fragments;
= 0.01 x 0.1 = 0.001
The identification field is a unique 16-bit value assigned to an IPv4 packet, when a packet is fragmented for transmission, its field is used to collate the unique fragments in the packet.
<span>The newest android os is:
Android 7.0 Nougat
</span>
Answer:
Syntax error
Explanation:
This is a type of error that occurs when there is a problem with the code that makes it unable to compile and execute.
For example, making a conditional statement without using the correct parameters will result in a syntax error.
<span>You should do it if C. it will take less than two minutes to complete </span>
Answer:
item = "quesadilla"
meat = "steak"
queso = False
guacamole = False
double_meat = False
base_price = 4.5
if item == "quesadilla":
base_price = 4.0
elif item == "burrito":
base_price = 5.0
if meat == "steak" or meat == "pork":
base_price += 0.50
if meat == "steak" and double_meat:
base_price += 1.50
elif meat == "pork" and double_meat:
base_price += 1.50
elif double_meat:
base_price += 1.0
if guacamole:
base_price += 1.0
if queso and item != "nachos":
base_price += 1.0
print(base_price)
Explanation:
- Use a conditional statement to check if meat is steak or pork then add 0.50 to base_price
.
- Check if the meat is steak or pork, then double_meat adds 1.50 or 1.0 otherwise
.
-
Check if meat is steak and its double_meat
, then add 1.50 and if its for guacamole, then add 1.00 to base_price
. If queso is there and item is not nachos, add 1.00 to base_price
.
- Finally when item is nachos, no need to add any money to base_price
.
