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2 years ago

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The unit we use to measure bending moment is... A kg B N C Nm D MPa

Computers and Technology

1 answer:

yaroslaw [1]2 years ago

3 0

The unit we use to measure bending moment is Newton m Bending second is a degree of the bending impact that may arise while an outside pressure (or second) is implemented to a structural element.

<h3>How to calculate the bending moment?</h3>

Calculate Bending = (Perpendicular to the pressure) Bending second is a torque implemented to every aspect of the beam if it becomes reduced in two - everywhere alongside its length.

The applies a clockwise second (torque) to the , and a counter-clockwise second to the. Moments and torques are measured as pressure elevated via way of means of a distance so that they have as unit newton meters or pound-foot.

Read more about the kilogram:

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2 years ago

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The received power will be 1.243 nW

We're given:

frequency $f$ = 150MHz

distance of the receiver $d$ = 32.2 km=32200m

Power of transmitter $P_{t}$ = 3W

Antenna gain = 8dB

To find :

Power received $P_{r}$

$P_{r}= \frac{P_{t} *G_{t}*G_{r}* \lambda^2 }{16*\pi^2*d^2}$

where $G_{t$ is transmit gain and $G_{r$ is receive gain as refrenced to isotropic source

⇒wavelength $\lambda = \frac{c}{f}$ where c is the speed of the light

⇒ $\lambda = \frac{3*10^8}{150*10^6} =2m$

$G_{t}= 1*1.64$ ( value of $dipole$ = 1.64)

Now,

Antenna gain $=8dB$ ( in decibals)

⇒ $10log(x)=8$

⇒ $x=10^0^.^8=6.3095$

⇒ considering isotropic receiver

⇒ $G_{r}=6.3095*1.64=10.3477$ ( $dipole$ =1.64)

Now , using the formula

$P_{r}= \frac{3 *1.64*10.3477 *2^2 }{16*\pi^2*32200^2}=1.2437*10^-^9$

Hence The received power will be 1.243 nW

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2 years ago