3 years ago

To inscribe a hexagon inside of a circle, which length should you set your compass in order to draw the sixth vertices?

1 answer:

4 0

The vertices are on the circle
that means that the length should be the radius

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Im pretty sure its -y^2+3y+13x-3

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g100num [7]

4-4=0

anything x 0=0

your answer is 4

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Lina20 [59]

Answer:

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s2008m [1.1K]

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stellarik [79]

f(x) + n - move the graph n units up

f(x) - n - move the graph n units down

f(x + n) - move the graph n units to the left

f(x - n) - move the graph n units to the right

---------------------------------------------------------------------------------------

$f(x)=-\dfrac{1}{5}x^2\\\\f(x+5)=-\dfrac{1}{5}(x+5)^2\\\\f(x+5)+2=-\dfrac{1}{5}(x+5)^2+2$

<h3>B. Moved 2 units up and 5 units to the left.</h3>

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3 years ago