Answer:
≈0.487
Step-by-step explanation:
I think this is your full question right?
Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:
Length Frequency
0-19 17
20-39 38
40-59 19 20 to 39 seconds.
60+ 20 to 4
Here is my anwer:
experimental probability = relative frequency =
Total frequencies = 17 + 38 +18 + 4 = 78
P(20 to 39s) = 38/78 ≈0.487
Answer:
Step-by-step explanation:
I'm not sure my way is going to be any quicker or better. Let's take an example.
Suppose you start with 456
Put a decimal at the end of the 6. You get 456.
Shift the decimal to the left one place 45.6
Divide by 2
22.8 (done mentally)
Note: dividing by 2 is easier than dividing by 5. Or multiplying by 5 for that matter.
Check the result.
456 * 5/100 =2280 / 100.
Shift a decimal 2 places to the left.
22.80 which agrees with your result.
Answer:
11/18
Step-by-step explanation:
The desired probability is the sum of ...
... (probability of choosing a coin) × (p(heads) on that coin)
Since the coins are chosen at random, we assume the probability of choosing a given coin is 1/3. Then ...
... p(heads) = (1/3)·(1/2) + (1/3)·1 + (1/3)·(1/3) = 1/6 + 1/3 + 1/9 = (3 +6 + 2)/18
... p(heads) = 11/18
Yes 3 ears of corn cost $1