The new volume of the hydrogen gas in the balloon is 1.5 L.
<u>Explanation:</u>
At STP, Temperature, T1 is 0° C = 0 + 273 K = 273 K
Pressure, P1 = 1 atm
Here given volume, V1 = 3.60 L
Balloon at sea,
Pressure, P2 = 2.5 atm
Temperature, T2 = 10° C = 10 + 273 = 283 K
Volume, V2 = ?
Here, we have to use the equation,
We have to rearrange the equation to get V2 as,
Now plugin the values as,
V2 =
= 1.5 L
So the new volume of the hydrogen gas is 1.5 L.