The given molarity of sodium hydroxide solution = 2.0 M
The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH
Converting 65 mL to L:
![65mL*\frac{1L}{1000mL} =0.065L](https://tex.z-dn.net/?f=65mL%2A%5Cfrac%7B1L%7D%7B1000mL%7D%20%3D0.065L)
Calculating the moles of NaOH in the final solution:
![0.065L * \frac{0.6 mol}{L} =0.039mol](https://tex.z-dn.net/?f=0.065L%20%2A%20%5Cfrac%7B0.6%20mol%7D%7BL%7D%20%3D0.039mol)
Finding out the volume of 2.0 M solution taken to prepare the final solution:
![0.039 mol * \frac{1L}{2.0mol}=0.0195L*\frac{1000mL}{1L} =19.5mL](https://tex.z-dn.net/?f=0.039%20mol%20%2A%20%5Cfrac%7B1L%7D%7B2.0mol%7D%3D0.0195L%2A%5Cfrac%7B1000mL%7D%7B1L%7D%20%3D19.5mL)
Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.
A physical change has occured, Boiling water is a physical change not a chemical one, now if you're talking about the electric current, that had not changes either. it may rearrange the molecules, but it does not change the fundamental properties of the substance.
1, 4, 1, 2, 1
Explanation:
We have the following chemical reaction:
MnO₂ + HCl → MnCl₂ + H₂O + Cl₂
To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.
So the balanced chemical equation is:
MnO₂ + 4 HCl → MnCl₂ + 2 H₂O + Cl₂
Learn more about:
balancing chemical equations
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Answer:
239.15. OR round down 239
Explanation:
Answer:
I can't answer that Po sorry