Answer:
Explanation:
Let's break it down:
- Butane- A 4 carbon alkane
- Methyl - A CH₃ group
- 2,2 - Both the Methyl groups are attached at carbon 2
We can now draw the structure of 2,2-dimethyl butane using the following steps:
- Draw the backbone (butane)
- Draw the substituents (2 methyl groups at carbon 2)
Mass of X₄Z₅= 378.621 g
<h3>Further explanation</h3>
Given
3.89 x 10²³ molecules/formula units of X₄Z₅
Required
Mass of X₄Z₅
Solution
1 mol = 6.022 x 10²³ particles(molecules, atoms, ions)
N = n x No
No = Avogadro's number
n = mol
Conversion to mol :
n = N : No
n = 3.89 x 10²³ : 6.022 x 10²³
n = 0.646
MW X₄Z₅ :
= 4 x 76.15 + 5 x 56.3
= 304.6 + 281.5
= 586.1 g/mol
Mass :
= mol x MW
= 0.646 x 586.1
= 378.621 g
Answer:
127.28 mmHg
Explanation:
The molar fraction of oxygen in dry air at 760 mmHg is 20.9%. This molar fraction is not affected too much by the height, so it may be taken as a constant. The partial pressure of oxygen may be calculated as:
So, if the total pressure is 609 mmHg,
mmHg.
Answer:
grams of oxygen = 21.40 g
Explanation:
octane → C8H18
The chemical reaction needs to be represented with a chemical equation before solving. The equation also need to be balanced.
C8H18 + O2 → CO2 + H2O
Balanced equation
2C8H18 + 25O2 → 16CO2 + 18H2O
Molar mass of octane = 12 × 8 + 18 = 96 + 18 = 114 g
Mass of octane in the chemical equation = 2 (114) = 228 g
molar mass of oxygen = 32 g
mass of oxygen in the chemical equation = 25 × 32 = 800 g
if 228 g of octane react with 800 g of oxygen
6.1 g of octane will require ? grams of oxygen
cross multiply
grams of oxygen = 6.1 × 800/228
grams of oxygen = 4880
/228
grams of oxygen = 21.4035087719
grams of oxygen = 21.40 g
