Answer:
A. From 25,0 g of aluminium you will produce 0,927 moles of aluminium chloride
B. From 30,0 g of chlorine gas you will produce: 0,282 moles of aluminium chloride
Explanation:
a. The reaction that you have in this problem is:
3 Cl₂ + 2 Al → 2 AlCl₃
25,0 g of aluminium are:
25,0 ₓ = 0,927 moles
As Al:AlCl₃ ratio is 1, from 25,0 g of aluminium you will produce: <em>0,927 moles of aluminium chloride</em>
b. 30,0 g of chlorine gas are:
30,0 ₓ = 0,423 moles of Cl₂
As Cl₂:AlCl₃ ratio is ³/₂:
0,423 moles of Cl₂ ₓ = <em>0,282 moles of aluminium chloride</em>
Thus, from 30,0 g of chlorine gas you will produce: <em>0,282 moles of aluminium chloride</em>
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I hope it helps!
