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Natasha2012 [34]
3 years ago
7

Arla and kal both work in jobs they get paid by the hour in their first week on the job they each worked 40 hours and together t

here total earnings were $1300 in their second week on the job business was slow so arla worked 20 hours and kal worked 16 hours their total pool earning was $580 what is each persons hourly wage
Mathematics
1 answer:
gladu [14]3 years ago
4 0

Answer:

Arla - $15, Kal - $17.5

Step-by-step explanation:

Let $x be Arla's hourly wage and $y be Kal's hourly wage.

1. In the first week on the job they each worked 40 hours and earned $(40x+40y) together. Their total earnings were $1300, so

40x+40y=1300.

2. In the second week on the job business was slow so Arla worked 20 hours and earned $20x, Kal worked 16 hours and earned $16y, $(20x+16y) in total. Their total pool earning was $580, so

20x+16y=580.

3. Solve the system of two equations:

\left\{\begin{array}{l}40x+40y=1300\\20x+16y=580\end{array}\right.\Rightarrow \left\{\begin{array}{l}40x+40y=1300\\40x+32y=1160\end{array}\right..

Subtract them:

40y-32y=1300-1160,\\ \\8y=140,\\ \\y=\$17.5.

Then

40x+40\cdot 17.5=1300,\\ \\40x=1300-700,\\ \\40x=600,\\ \\x=\$15.

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Simplify the expression. -14 x 8 x 1/4 + (-22)
pochemuha
<span>-14 x 8 x 1/4 + (-22)

Apply BODMAS

Open the brackets:
</span>-14 x 8 x 1/4 + (-22) = <span>-14 x 8 x 1/4 -22

Division
-14 x 8 x (1/4) - 22 = </span><span>-14 x 8 x 0.25 - 22
</span><span>
Multiplication
</span><span>(-14 x 8 x 0.25 )- 22 = -28 - 22
</span><span>
Subtraction
-28-22 = -50

Correct answer: A <-50>




</span>
8 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
Please Help me with the last three questions!<br> It is urgent!
MrMuchimi
Answers:
1. X= 0
2. X= 0
3. X=3

You can use this method to solve them step by step, hope it will help!

8 0
3 years ago
Mike got in and elevator and whent down 3 floors. he meant to go to a lower level,so he stayed on the elevator and when down 3 m
Naily [24]
It is negative six because down three is -3 so 3+3 =6 but the numbers are negative so the answer is -6
7 0
3 years ago
Select the factors of 6ab + 3ay − 2bx − xy.
V125BC [204]
Answer
<span>A. (3a − x)(2b + y)

cause

</span><span> (3a − x)(2b + y) = 6ab + 3ay -2bx -xy (expand by using distributive property)</span>
3 0
3 years ago
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