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2 years ago

If m∠A = m∠B and m∠A + m∠C = ∠D, then m∠B + m∠C = ∠D Which property is shown?

Mathematics

1 answer:

Ad libitum [116K]2 years ago

6 0

Answer:

Substitution Property

Step-by-step explanation:

So we know that:

$m\angle A=m\angle B$

And we also know that:

$m\angle A+m\angle C=\angle D$

And by using a specific property, we get that:

$m\angle B+m\angle C=\angle D$

Essentially, we substituted B for A.

So, this is an example of the substitution property, where if two sides/angles are congruent, we can substitute them for each other.

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Kengi buys 3 yds of fabric for $7.47 then he realizes that he needs 2 more yds. How much will the extra fabric cost?

ss7ja [257]

7.47/3 = 2.49. 2.49 is the base cost per yard. 2.49*2 is 4.98. The extra fabric will cost him $4.98

Also pro tip always put the unit of measurement in when describing, whether it'd be a dollar sign or other thing.

4 0

3 years ago

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The fraction that's equivalent to 6/7. The sum of the numerator and the denominator is 78. What is the fraction?

a_sh-v [17]

6*6= 36
7*6- 42

36+42= 78.

The fraction is 36/42.

8 0

2 years ago

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A brick of mass 4 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 3 cm. The spring is t

Zielflug [23.3K]

Answer:

Step-by-step explanation:

In this system we have the force of the spring and the gravitational force. The equation that describes that is

$F_{s}+F{g}=ma\\k(y_0+y)-mg=ma$

where y0 is the equilibrium position when the string is free and y0+y is the new equilibrium position when the object is hanged of the string. By replacing by derivatives we have

$ky_0+ky-mg=ma\\mg+ky-mg=ky=ma\\\\ky=m\frac{d^2y}{dt^2}\\\\my''+ky=0$

the solution for this differential equation is (by using the characterisic polynomial)

$y(x)=Acos(kt)+Bsin(kt)\\k=\omega^2m$

hope this helps!!

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3 years ago

Read 2 more answers

Tim has to cover 3 tanks completley with paint.

bija089 [108]

answer:

<h3>Total surface area of 3 tanks=34.3 m^2</h3><h3>7 tins of paint are required.</h3>

Solution,

diameter of tank=1.4 m

Height of tank=1.9 m

Given tank has top and bottom 

Now, The total surface area of cylinder tank is given by:

 $tsa = 2\pi \: {r}^{2} + (2\pi \: r \: ) \times h$ 

r( radius of tank)=

 $\frac{diameter}{2} = \frac{1.4}{2} = 0.7 \: m$ 

h(height of tank)=1.9 m

TSA of 1 tank

=

 $2 \times 3.14 \times {(0.7)}^{2} + 2 \times 3.14 \times 0.7 \times 1.9 \\ = 11.435 \: {m}^{2}$ 

TSA Of 3 tanks

=

 $3 \times 11.435 \: {m}^{2} \\ = 34.3 \: {m}^{2}$ 

Given a tin of plate covers 5m^2 area.

No.of tins required:

1 tin 5m^2

x tin 34.3 m^2

 $5x = 34.3(cross \: multiplication) \\ or \: x = \frac{34.3}{5} \\ x = 6.86 \\ x = 7 \: tins$ 

therefore 7 tins are required.

Hope this helps...

Good luck on your assignment....

8 0

2 years ago

A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

lesantik [10]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

⇒

$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

0.997402 = 99.7402 %

4 0

3 years ago