Hello,
To solve we need to factor y^2-2y-35:
(y-7)(y+5)=0
Now solve for :
(When will (y-7)(y+5)equal zero?)
When y-7=0 or y+5=0
Solve for the 2 equations above and;
y= 7,-5
Hope this helps, have a great day!
Answer:
60 students passed, and 75 appeared in examination.
Step-by-step explanation:
Let's say s is the total number of students and p is the number of students who passed.
80% of the students passed, so:
0.8 s = p
If there were 10 less passers, and 15 less students (5 less failures), then the ratio of passers to failures would be 5/1.
(p − 10) / (s − p − 5) = 5 / 1
Simplify the second equation:
p − 10 = 5 (s − p − 5)
p − 10 = 5s − 5p − 25
6p = 5s − 15
Substitute the first equation.
6 (0.8 s) = 5s − 15
4.8 s = 5s − 15
0.2 s = 15
s = 75
p = 0.8 s
p = 60
60 students passed, and 75 appeared in examination.
Answer:
It would be the third one hope i helped
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
The answer is 10 because there are 20 days and no home work is due on 7 of those days so that’s 13 days with homework from math or writing. Then you take the three days where it was just math and subtract that to get 10 days of writing.
Answer:
I can't see anything or any questions.....?
