<h2>Answer</h2>
2
<h2>Explanation</h2>
First, we are going to use the law of fractional exponents: ![a^{\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
We can infer form our expression that
and
, so let's replace the values:
![a^{\frac{1}{n} =\sqrt[n]{a}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D)
![16^{\frac{1}{4} }=\sqrt[4]{16}](https://tex.z-dn.net/?f=16%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%3D%5Csqrt%5B4%5D%7B16%7D)
Notice that we can also decompose 16 into prime factors to get
, so we can rewrite our expression as follows:
![\sqrt[4]{16}=\sqrt[4]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%3D%5Csqrt%5B4%5D%7B2%5E4%7D)
Finally, we can use the rule of radicals:
, so:
![\sqrt[4]{2^4}=2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E4%7D%3D2)
He could only make one team, considering that if you do 12-9, you are left with 3, and Jason wants to have his team consisted of 9 players. However, if you make 3 teams with 4 players on each team, or 4 teams with 3 players on each team, you could do that as well.
Answer:
51 cm
Step-by-step explanation:
There is a well known property of medians of triangle
In any triangle, medians are concurrent and their common intersection point divides each median in proportion 2:1, counting the median parts from the vertex.
So, if G F = 17 cm, then AG = 34 cm, and the entire median C F = 17 +34 = 51 cm
abcdefghijklmnopqrstuvwxyz
12v + 3b = 243
4v + 4b = 204....multiply by -3
-------------------
12v + 3b = 243
-12v - 12b = - 612 (result of multiplying by -3)
-------------------add
-9b = - 369
b = -369/-9
b = 41 <=== each bus holds 41 students
4v + 4b = 204
4v + 4(41) = 204
4v + 164 = 204
4v = 204 - 164
4v = 40
v = 40/4
v = 10 <== each van holds 10 students