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BlackZzzverrR [31]
3 years ago
10

Please solve for x and is it complementary or supplementary

Mathematics
1 answer:
Viktor [21]3 years ago
5 0
The answer is 10 x and i think complementary but i could be wrong so you may want someone else to answer that
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The sum of four times a number and 18 is the same as the difference of fourteen and twice a number
Citrus2011 [14]
4x+18=14-2x \\ 4x=-4-2x \\ 6x=-4 \\ x= \frac{2}{3}
4 0
4 years ago
I need help with this math problem and how you solved it...
Galina-37 [17]
To get angle Y, you have to do 90 - 27 to get the other angle in the triangle and you get 63. Then you do 180 - (63+51) which is 66. 

Angle Y = 66
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3 years ago
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What is 3/10 of 400 in percentage
son4ous [18]
3/10 of 400 = 120
in percentage shall be as follow
120/400 * 100  = 30%
6 0
3 years ago
         will give brainleast
Montano1993 [528]
9 x _ = 162 (ABCD) 162 divided by 9 = 18 
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6 x 18 = 108ft2

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7 0
3 years ago
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System practice problems
nydimaria [60]

Looking at the first system of equations,

16x - 10y = 10

-8x - 6y = 6

If we multiply both sides of the second equation by 2, the coefficient of x is exactly the negative of the coefficient of x in the first equation.

-8x - 6y = 6

⇒   2 (-8x - 6y) = 2 (6)

⇒   -16x - 12y = 12

By combining this new equation with the first one, we can eliminate x and solve for y :

(16x - 10y) + (-16x - 12y) = 10 + 12

⇒   -22y = 22

⇒   y = -1

Then we just solve for x by replacing y in either equation.

16x - 10y = 10

⇒   16x - 10 (-1) = 10

⇒   16x + 10 = 10

⇒   16x = 0

⇒   x = 0

The main idea behind elimination is combining the given equations in just the right amount so that one of the variables disappears. The "right amount" involves using the LCM of the coefficients of a given variable. In this example, the x-coefficients had LCM(8, 16) = 16, so we only had to scale one of the equations (the one with -8x) to cancel all the x terms.

If we wanted to eliminate y first instead, we first note that LCM(6, 10) = 30. To get 30 as a coefficient on y, in the first equation we would have multiplied by 3:

16x - 10y = 10

⇒   3 (16x - 10y) = 3 (10)

⇒   48x - 30y = 30

And in the second equation, we would have multiplied by -5 (negative so that upon combining the equations, we end up with -30y + 30y = 0):

-8x - 6y = 6

⇒   -5 (-8x - 6y) = -5 (6)

⇒   40x + 30y = -30

Now combining the two scaled equations gives

(48x - 30y) + (40x + 30y) = 30 + (-30)

⇒   88x = 0

⇒   x = 0

We then solve for y :

16x - 10y = 10

⇒   -10y = 10

⇒   y = -1

so we end up with the same solution as before.

8 0
3 years ago
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