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ser-zykov [4K]
3 years ago
9

Can someone help me with my Algebra 2 work? Its problems 23-28 all.

Mathematics
2 answers:
vazorg [7]3 years ago
8 0

23) x^2 * 8

24) x^3 - 15

25) (x/4) + 5

26) 4 less than the product of 8 and a number is 16

27) The sum of a number and 3 divided by 4 is 5

28) 3 less than 4 times a number squared is 13

LenaWriter [7]3 years ago
8 0

23)

product: means multiply

square: means ()²

8n²

24)

less: means subtract

than: means switch the order

cube: means ()³

n³ - 15

25)

more: means add

than: means switch the order

quotient: means divide

n/4 + 5

26)

8x - 4 = 16

four less than the product of eight and a number is sixteen

27)

(x + 3)/4 = 5

the quotient of three more than a number and four is five

28)

4y² - 3 = 13

three less than the product of the square of a number and four is thirteen




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HLEPPPPPP!!!!!
Ksenya-84 [330]

Answer:

Solutions:-5,0,9,6

Not solutions: 12.5,10

Explanation:

The inequality that was given is:

20 > 5 + 3x

First, group similar terms;

20 - 5 < 3x

15 < 3x

x = 5

Thus, the solutions are:-3.5, 5, 4 3/4, -15

The not solutions are:-10 2/3, 129,

Hope this helps! :)

7 0
3 years ago
Can someone solve and explain how to do these absolute equations for 40 points? I'll give brainliest to the best correct answer.
irga5000 [103]

Answer:

Explanation Below

Step-by-step explanation:

1.    -4 + | x - 1 | = 3

= -4 + | x - 1 | + 4 = 3 + 4

= | x - 1 | = 7

= x - 1 = -7     or    x - 1 = 7

= x = -6 or x = 8

2.   6 + 4 | 2x + 6| = 14

 = 6 + 4 | 2x + 6 | - 6 = 14 - 6

 = 4 | 2x + 6 | = 8

 = 4 | 2x + 6 | / 4 = 8/4

 = 2x + 6 = -2          or         2x + 6 = 2

 = x = -4    or     x = -2

3.  -10 + | -6 - x | = 1

  = -10 + | -6 + x | + 10 = 1 + 10

  = | -6 - x | = 11

  =  -6 - x = -11     or   -6 - x = 11

  = x = -17        or       x = 5

4.    | 7 - 2x | + 4 = 5

   = | 7 - 2x | + 4 - 4 = 5 - 4

   = | 7 - 2x | = 1

   = 7 - 2x = -1            or             7 - 2x = 1

   = x = 3       or   x = 4

Here are the Steps:

SOLVING EQUATIONS CONTAINING ABSOLUTE VALUE(S)

Step 1: Isolate the absolute value expression.

Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.

Step 3: Solve for the unknown in both equations.

Step 4: Check your answer analytically or graphically.

Hopes this Helps :D

Mark me Brainliest : )

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Step-by-step explanation:

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