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3 years ago

Can someone help me with my Algebra 2 work? Its problems 23-28 all.

Mathematics

2 answers:

vazorg [7]3 years ago

8 0

23) x^2 * 8

24) x^3 - 15

25) (x/4) + 5

26) 4 less than the product of 8 and a number is 16

27) The sum of a number and 3 divided by 4 is 5

28) 3 less than 4 times a number squared is 13

LenaWriter [7]3 years ago

8 0

23)

product: means multiply

square: means ()²

8n²

24)

less: means subtract

than: means switch the order

cube: means ()³

n³ - 15

25)

more: means add

than: means switch the order

quotient: means divide

n/4 + 5

26)

8x - 4 = 16

four less than the product of eight and a number is sixteen

27)

(x + 3)/4 = 5

the quotient of three more than a number and four is five

28)

4y² - 3 = 13

three less than the product of the square of a number and four is thirteen

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Jell E. Bean owns the local frozen yogurt shop. At her store, customers themselves a bowl of frozen yogurt. Jell E. Bean charges

uysha [10]

Answer:

Step-by-step explanation:

Unit rate = $32/(5 pounds) = $6.40/pound

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$6.40/pound × (1 pound)/(16 ounces) = $0.40/ounce]

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Cost = (number of pounds) × $6.40/pound

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2 years ago

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

8 0

3 years ago

Using addition rules, show how to add the two real numbers. 7 + (-14)

Debora [2.8K]

Hello there! Using the rules of addition, we can identify that when adding a positive to a negative number, the result shifts toward the positive side but takes the sign of the greater number. It will be demonstrated in this problem to simplify how problems like this are solved:

Step 1: Rewrite the problem

-14 + 7 = ?

Step 2: Since we’re adding 7 to a negative number, that means the negative number decreases by the quantity it’s being added by.

This means we would have to really subtract 7 from 14 to get 7.

Step 3: Keep the sign of the greater number

Since 14 is greater than 7, we will keep the negative sign in accordance.

Step 4: Simplify

-14 + 7 = -7

Using the rules of addition, we will find that -14 + 7 = -7. If you need additional help, let me know and I will gladly assist you.

5 0

1 year ago

Read 2 more answers

Please simplify this it would help a lot

dexar [7]

Answer:

-1

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

19)

Elena-2011 [213]

Answer:

The correct answer is: Option D) 5

Step-by-step explanation:

Given equation is:

$3(x + 2) + x = 2x + 16$

In order to find that which values of x makes the equation true, we have to put each value of x in the equation. When both sides of equations will be equal, that value of x will be true for the equation.

Putting x = 2

$3(2 + 2) + 2 = 2(2) + 16\\3(4)+2 = 4+16\\12+2 = 20\\14 \neq 20$