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Debora [2.8K]
3 years ago
8

Which process can separate out the solute from the solvent?

Physics
2 answers:
nadezda [96]3 years ago
7 0

EVAPORATION because you can take out the dissolved substance with it.

MAVERICK [17]3 years ago
3 0

c) Evaporation

hope this helps!

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A block of mass 5 kg is placed on a rough table having a coefficient of static friction μs = 0.2.What is the force required to m
just olya [345]

Answer:

<em>We need to (at least) apply a force of 9.8 N to move the block</em>

Explanation:

<u>Second Newton's Law</u>

If a net force F_n different from zero is applied to an object of mass m, then it will move at an acceleration a, given by

F_n=ma

If we apply a force F to an object placed on a rough surface, the only way to make it move is to beat the friction force  which is given by

F_r=\mu F_N

Where \mu is the static friction coefficient and F_N is the normal force exerted by the table to the object. Since there is no motion in the vertical direction the normal force equals the weight of the object:

F_N=mg=5\ kg\ 9.8\ m/s^2=49\ N

The friction force is

F_r=0.2 (49)=9.8\ N

Thus, we need to (at least) apply a force of 9.8 N to move the block

5 0
4 years ago
Give an example of Newton's 1st law​
Vesna [10]

Answer:

A ball moving until gravity pulls it back down to the ground

Explanation:

5 0
3 years ago
A catcher catches a 150g baseball traveling horizontally at 25 m/s. If the ball takes 20.ms to stop once it is in contact with t
rosijanka [135]

Answer:

The magnitude of the force exerted by the ball on the catcher is 1.9 × 10²  N

Explanation:

Hi there!

Let´s find the acceleration of the ball that makes it stop when caught by the catcher. The acceleration can be calculated from the equation of velocity considering that it is constant:

v = v0 + a · t

We know that initially the ball was traveling at 25 m/s, so, if we consider the position of the catcher as the origin of the frame of reference, then, v0 = -25 m/s. We also know that it takes the ball 20 ms (0.02 s) to stop (i.e. to reach a velocity of 0). Then using the equation of velocity:

v = v0 + a · t

0 m/s = -25 m/s + a · 0.020 s

25 m/s/ 0.020 s = a

Now, using the second law of Newton, we can calculate the force exerted by the catcher on the ball:

F = m · a

Where:

F = force.

m = mass of the ball.

a = acceleration.

F = 0.150 kg · (25 m/s/ 0.020 s) = 1.9 × 10²  N

According to Newton´s third law, the force exerted by the ball on the catcher will be of equal magnitude but opposite direction. Then, the force exerted by the ball on the catcher will have a magnitude of 1.9 × 10²  N.

3 0
4 years ago
Coil springs are widely used in industry. Those used in scientific instruments must be manufactured to exhibit consistent perfor
Strike441 [17]

Answer:

33627.4 N/m

Explanation:

By Hook's law F = k x

where F= force applied

K= Spring constant

x= distance it compresses.

Since the force applied in this case will be the weight of the object that causes it to compress, so, the weight will be (175 * 9.8) = 1715N force which causes a compression (x) of 0.0510m.

So,

F = K x

K = F / x

K = 1715 / 0.0510

K = 33627N/m

5 0
4 years ago
Is it right? correct me if im wrong
jeka57 [31]

Answer:

i think it is right

Explanation:

8 0
3 years ago
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