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Tems11 [23]
3 years ago
7

A 1.2-kg mass is projected from ground level with a velocity of 31.3 m/s at some unknown angle above the horizontal. A short tim

e after being projected, the mass barely clears a 16-m tall fence. Disregard air resistance and assume the ground is level. What is the kinetic energy of the mass as it clears the fence
Physics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

The kinetic energy will be "399.65 J".

Explanation:

Given:

Mass,

m = 1.2 kg

Velocity,

v = 31.3 m/s

The total energy of mass will be:

⇒ E=K+U

or,

⇒ E=.5mv^2+mgh

By putting the values, we get

        =.5(1.2)(31.3)^2+0

        =0.6\times 979.69+0

        =587.81 \ J

Since,

The system's total energy is unchanged, then

⇒ E=K+U

or,

⇒ E=K+mgh

   587.81=K+1.2(9.8)(16)

   587.81=K+188.16

          K=587.81-188.16                

               =399.65 \ J

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Lynna [10]
If mass doubled and the force remained constant then the acceleration would also double

Hopes this helps
5 0
3 years ago
Olivia is on a swing at the playground. if the swing is moving from W to Z, at which point is her kinetic energy increasing and
s2008m [1.1K]

Answer:

from W-Z.. i think on a swing you get your most potential energy at W and Z is where you go up so Z would be where the kinetic energy increased and W is where potential energy decrease

Explanation:

hope this helps

4 0
2 years ago
Which of the following is a true statement about work?
Over [174]

Answer:

It measure the effort it takes for an object to move

Explanation:

Work done is the force applied to move a body through a particular distance.

It can also to be said to be a measure of the effort it takes for an object to move.

The unit of work done is in Joules.

 To find work done, we use the expression below:

       Work done  = Force x distance

5 0
3 years ago
Could someone explain to me how to got the answer B, thank you very much​
Mnenie [13.5K]

Answer:

since -6 lasted for 5 seconds, multiplying both would result in -30

3 lasted for 10 seconds, so multiplying both would give +30

average = ( 30 + (-30) ) / 2

30 -30 is already equal to zero, so the answer should be 0

4 0
3 years ago
Starting at t = 0 s , a horizontal net force F⃗ =( 0.285 N/s )ti^+(-0.460 N/s2 )t2j^ is applied to a box that has an initial mom
Irina-Kira [14]

Answer:

Explanation:

We know that Impulse = force x time

impulse = change in momentum

change in momentum = force x time

Force F = .285 t -.46t²

Since force is variable

change in momentum = ∫ F dt  where F is force

= ∫ .285ti - .46t²j dt

= .285 t² / 2i - .46 t³ / 3 j

When t = 1.9

change in momentum = .285 x 1.9² /2 i  -  .46 x 1.9³ / 3 j

= .514i - 1.05 j

final momentum

= - 3.1 i + 3.9j +.514i - 1.05j

= - 2.586 i + 2.85j

x component = - 2.586

y component = 2.85

7 0
3 years ago
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