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Ugo [173]
3 years ago
8

All boundary points of a rational inequality that are found by determining the values for which the denominator is equal to zero

should always be represented by plotting an open circle on a number line. B. All boundary points of a rational inequality should always be represented by plotting a closed circle on a number line. C. All boundary points of a rational inequality should always be represented by plotting an open circle on a number line. D. All boundary points of a rational inequality that are found by determining the values for which the numerator is equal to zero should always be represented by plotting an open circle on a number line.
Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0

Answer: All boundary points of a rational inequality that are found by determining the values for which the denominator is equal to zero should always be represented by plotting an open circle on a number line.

Step-by-step explanation:

Based on the options given in this question, it should be noted that the option that is true is that all boundary points of a rational inequality that are found by determining the values for which the denominator is equal to zero should always be represented by plotting an open circle on a number line.

Therefore, the correct option is A.

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If f(x) = 3x + 2, what is f(5)?
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The 5 in the () is what the x is

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What is: ⅛ ( 64v + 24) =
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8v + 3.

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Find all the numbers for each shape
irina1246 [14]

Answer:

  • 1 = pentagon
  • 2 = diamond
  • 3 = square
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  • 6 = rectangle
  • 7 = oval
  • 8 = triangle
  • 9 = hexagon
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Step-by-step explanation:

Each half of a hanger divides the total weight in half. The right-most vertical has a total weight of 80/16 = 5. It consists of a square and a diamond, and we know the square is 1 more than the diamond. That means 2 diamonds weigh 5 -1 = 4. A diamond weighs 2, and a square weighs 3. The other half of that balance is a circle, which weighs 5.

The total of a square and oval is 10, so the oval is 10 -3 = 7. The two trapezoids weigh 20, so each is 10.

The second vertical from the left is a circle and diamond which will weigh 5+2 = 7. That makes the sum of a pentagon and rectangle also be 7. The 7+7 = 14 below the square on the left branch makes the total of that branch be 14+3 = 17, which is also the sum of the triangle and hexagon.

The weight below the rectangle at top left is 17+17 = 34, and the weight of that entire branch is 40. Thus the rectangle is 40-34 = 6, which makes the pentagon 7-6 = 1.

We require the sum of the triangle and hexagon be 17, with the triangle being the smaller value, and both being 9 or less (the trapezoid is the only figure weighing more than 9). Hence the triangle is 8 and the hexagon is 9.

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Answer:

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m = slope; b = y-intercept

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m = 3 = slope

b = -5 = y-intercept

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