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Ugo [173]
3 years ago
8

All boundary points of a rational inequality that are found by determining the values for which the denominator is equal to zero

should always be represented by plotting an open circle on a number line. B. All boundary points of a rational inequality should always be represented by plotting a closed circle on a number line. C. All boundary points of a rational inequality should always be represented by plotting an open circle on a number line. D. All boundary points of a rational inequality that are found by determining the values for which the numerator is equal to zero should always be represented by plotting an open circle on a number line.
Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0

Answer: All boundary points of a rational inequality that are found by determining the values for which the denominator is equal to zero should always be represented by plotting an open circle on a number line.

Step-by-step explanation:

Based on the options given in this question, it should be noted that the option that is true is that all boundary points of a rational inequality that are found by determining the values for which the denominator is equal to zero should always be represented by plotting an open circle on a number line.

Therefore, the correct option is A.

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The quadratic equation 2x^2+4x-30=0 has two solutions. one of the solutions is x=3 the other solution is?
BartSMP [9]

Answer:

2x^2+4x-30=0

Step-by-step explanation:

2x^2+10x-6x-30=0

2x(x+5)-6(x+5)=0

(2x-6)(x+5)=0

2x-6=0        x+5=0

x=6/2          x=-5

x=3

6 0
3 years ago
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Solve for x. And graph 7(3x+4)+2<156
blsea [12.9K]

7(3 \times x + 4) + 2 < 156 \\ 21 \times x + 28 + 2 < 156 \\ 21 \times x + 30 < 156 \\ 21 \times x < 156 - 30 \\ 21 \times x < 126 \\ x  <   \frac{126}{21}  \\ x < 6

8 0
3 years ago
Simplify.<br> √192<br><br> A. 8√3<br><br> B. 64√3<br><br> C. 10√6<br><br> D. 8√24
ale4655 [162]
The correct answer is:  [A]:  " 8 √3 " .
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Note:

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6 0
3 years ago
Can someone help me with these questions immediately? Thank you!
Scrat [10]

Answer:

35

................................................

5 0
3 years ago
3.
natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.

b) In matrix form this is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)

c) The determinant is

\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16

d) Find three determinants:

\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608

\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368

\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304

So,

x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19

e) If the store doubled all prices and inventory, then the new matrix is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)

7 0
3 years ago
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