Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer:
4.5 mph
Step-by-step explanation:
6 times 3 is 18.
18 divided by 4 is 4.5
Answer:
Ordered pairs are ( -3, 0) (0, 3)
Step-by-step explanation:
Now when your graphing, go up 3 spots in the y-axis ( up & down) and plot your point now do the same for your x-axis (( left and right), so go over to the left 3 places, and there now connect the 2 points and your done. Hope that helps!
Answer:
True
Step-by-step explanation:
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I don’t know what answers you have but I think it’s 23.4