Answer:
which grade u r in I'm in 10th grade and Indian
In 1, t<span>here are 6 outcomes for each die, so for three dice, the total combination is 6 x 6 x 6 = 216 outcomes. Hence, t</span><span>he probability of any individual outcome is 1/216 </span>
The outcomes that will add up to 6 are
<span>1+1+4 </span>
<span>1+4+1 </span>
<span>4+1+1 </span>
<span>1+2+3 </span>
<span>1+3+2 </span>
<span>2+1+3 </span>
<span>2+3+1 </span>
<span>3+1+2 </span>
<span>3+2+1 </span>
<span>2+2+2 </span>
<span>Hence the probability is </span><span>10/216 </span>
In 3, the minimum sum of the three dice is 3. so we start with this
<span>P(n = 3) </span>
<span>1+1+1 ; </span><span>1/216 </span>
<span>P(n = 4) </span>
<span>1+1+2 </span>
<span>1+2+1 </span>
<span>2+1+1 ; </span><span>3/216 </span>
<span>P(n = 5) </span>
<span>1+1+3 </span>
<span>1+3+1 </span>
<span>3+1+1 </span>
<span>1+2+2 </span>
<span>2+1+2 </span>
<span>2+2+1; </span><span>6/216
The sum in 3 is 10/216 or 5/108</span>
Let no red ribbons=x
no. Of blue ribbons=x+3
No. Of yellow ribb9ns=x+7
Totsl ribbons=28
28=x+x+3+x+7
28=3x+10
3x=28-10
3x=18
X=18/3
X=6
No .of red ribbons=6
No. Of blue ribbons=x+3=9
No. Of yellow ribbons=x+7=13
Answer:
0.6
Step-by-step explanation:
We know that there are 5 counters in total. 3 white and 2 black.
So we know that 3 out of 5 are white and 2 out of 5 are black.
Therefore the chance to get white is 3/5. And for black: 2/5.
We can turn these into decimals, 3/5 = 0.6 (You can make it 6/10 to make it easier.)
And 2/5 = 0.4 (You can make it 4/10 to make it easier.)
Answering the question, you should put your cross/marker on 0.6
Answer:
answer = -12
Step-by-step explanation:
substitute y as -3 and z as 4
3(-3) - 2(4) + 5
-9-8+5
-17+5
-12
