Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Point of Y intercept is (0,4)
Y1-Y2=m(X1-X2)
Plug in x,y into X2, Y2 m=slope
y-4=2(x-0)
y-4=2x
y=2x+4
Table
Plug in for x and y
x. y
0. 4
1. 6
2. 8
Answer: $940
Step-by-step explanation:
You multiply the 9540 by .10 because 10% turns into .10 and then when you multiply that which is.... 9540x.10= 954
Step-by-step explanation:
whaaaaaat ........how do we know that
Answer:
B
Step-by-step explanation:
Rate, in this case, is mph which can be written as miles/hours.
HTH :)
