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timofeeve [1]
2 years ago
12

What is. 3q + 2 (q+1)

Mathematics
2 answers:
Fudgin [204]2 years ago
5 0

Answer:

5q + 2

Explanation:

3q + 2(q + 1)

Distribute:

= 3q + (2)(q) + (2)(1)

= 3q + 2q + 2

Combine Like Terms:

= 3q + 2q + 2

= (3q + 2q) + (2)

= 5q + 2

NemiM [27]2 years ago
5 0

Answer:

5q+2

Step-by-step explanation:

3q+2q+2 <---------------------   distribute the 2 groups with 1 and q

5q+2 <--------------------------- combine like terms

this is the most simplified expression.

Hope this answera and work helps you understand algebra much better!!!

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A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
2 years ago
Factor the expression 4x + 32. Explain each step you take in the process.
irinina [24]

Step-by-step explanation:

1. What the GCF

the GCF is 4

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2. divide by 4

4(x+8) is the solution

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3 years ago
Read 2 more answers
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22 + (30 - 4) divided by 2

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