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3 years ago

Scenario for 300=60t

Mathematics

2 answers:

sergij07 [2.7K]3 years ago

7 0

T=5. 60 × 5 = 300. 300 ÷ 60 = 5. 300 ÷ 5 = 60

earnstyle [38]3 years ago

4 0

Do you need to find what t is? If so, do 300 divided by 60 to get the t isolated. which is, 5.

you can check by doing 60*5 which is 300

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Write the equation of the line parallel to 5x + y = -2 that goes through the point (2, -3).

gladu [14]

Answer:

y = -5x + 7

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Define

5x + y = -2

Random point (2, -3)

Step 2: Rewrite

y = -5x - 2

m = -5

Step 3: Write parallel line

y = -5x + b

-3 = -5(2) + b

-3 = -10 + b

7 = b

y = -5x + 7

8 0

3 years ago

A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p

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Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

step 1:-

Given sample size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

Population proportion of employed individuals who work at home at least once per week P = $\frac{x}{n} =\frac{41}{200} =0.205$

Q=1-P= 1-0.205 = 0.705

step 2:-

Now $\sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }$

=0.0015

step 3:-

Confidence intervals

using formula

$(P - Z_∝} \sqrt{\frac{P Q}{n},} (P + Z_∝} \sqrt{\frac{P Q}{n},$

$(0.205-2.58(0.0015),0.205+2.58(0.0015)\\0.20113,0.20887$

=0.20113,0.20887[/tex]

conclusion:-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

4 0

3 years ago

How do i even solve this?? i’m super confused anything would help. ty.

alukav5142 [94]

Answer:

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Your teacher messed up the question so just put the top right answer and ask your teacher if they did accidently miss-type.

Step-by-step explanation:

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${b}^{4} + 1$

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