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3 years ago

What is the equilibrium constant expression for the given system?

Chemistry

2 answers:

rewona [7]3 years ago

5 0

The question is incomplete, here is the complete question:

The given chemical equation follows:

$2H_2O\rightleftharpoons 2H_2+O_2$

What is the equilibrium constant expression for the given system?

<u>Answer:</u> The expression of equilibrium constant for the given equation is $K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

<u>Explanation:</u>

Equilibrium constant is the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The given chemical equation follows:

$2H_2O\rightleftharpoons 2H_2+O_2$

The expression for $K_{eq}$ for above equation follows:

$K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

Hence, the expression of equilibrium constant for the given equation is $K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

VashaNatasha [74]3 years ago

3 0

Answer: is A

Explanation:

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Klio2033 [76]

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3 years ago