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Alex
3 years ago
9

What is the equilibrium constant expression for the given system?

Chemistry
2 answers:
rewona [7]3 years ago
5 0

The question is incomplete, here is the complete question:

The given chemical equation follows:

2H_2O\rightleftharpoons 2H_2+O_2

What is the equilibrium constant expression for the given system?

<u>Answer:</u> The expression of equilibrium constant for the given equation is K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

<u>Explanation:</u>

Equilibrium constant is the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:  

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The given chemical equation follows:

2H_2O\rightleftharpoons 2H_2+O_2

The expression for K_{eq} for above equation follows:

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Hence, the expression of equilibrium constant for the given equation is K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

VashaNatasha [74]3 years ago
3 0

Answer: is A

Explanation:

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