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3 years ago

What is the equilibrium constant expression for the given system?

Chemistry

2 answers:

rewona [7]3 years ago

5 0

The question is incomplete, here is the complete question:

The given chemical equation follows:

$2H_2O\rightleftharpoons 2H_2+O_2$

What is the equilibrium constant expression for the given system?

<u>Answer:</u> The expression of equilibrium constant for the given equation is $K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

<u>Explanation:</u>

Equilibrium constant is the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The given chemical equation follows:

$2H_2O\rightleftharpoons 2H_2+O_2$

The expression for $K_{eq}$ for above equation follows:

$K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

Hence, the expression of equilibrium constant for the given equation is $K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

VashaNatasha [74]3 years ago

3 0

Answer: is A

Explanation:

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2NaClO3 ——> 2NaCl + 3O2

Alborosie

Answer:

<h3>1) 208.09 g</h3><h3>2) 7.11 × 10²² particles</h3>

<h2>Explanation:</h2><h3>NUMBER ONE</h3>

<u>Find moles of Known Substance (NaCl)</u>

Moles of NaCl = mass ÷ molar mass

= 114.25 g ÷ 58.44 g/mol

= 1.955 mol

<u>Use Mole Ratio of Known to Unknown (NaCl : NaClO₃) to Determine Moles of Unknown</u>

The mole ratio of NaCl to NaClO₃ is 2 to 2 or simply 1 to 1.

This means that for each mole of NaCl produced the same number of moles of NaClO₃ was decomposed.

∴ since moles of NaCl = 1.955 mol,

then moles of NaClO₃ = 1.955 mol

<u>Find Mass of Unknown </u>

Mass of NaClO₃ = moles × molar mass

= 1.955 mol × 106.44 g/mol

= 208.09 g

<h3>NUMBER TWO</h3>

<u>Determine the Moles of Known (O₂)</u>

moles of O₂ = (volume × density) ÷ molar mass

= (68.30 L × 0.0828 g/L) ÷ 32 g/mol

= 0.177 mol

<u>Use Mole Ratio of Known to Unknown (O₂ : NaClO₃) to Determine Moles of Unknown</u>

Mole ratio of O₂ : NaClO₃ is 3 : 2. Therefore for each mole of oxygen produced, ²/₃ the moles of NaClO₃ is produced.

∴ if moles of O₂ = 0.177 mol

then moles of NaClO₃ = 0.177 mol × ²/₃

= 0.118 mol

<u>Find the Number of Particles of Unknown</u>

Number of particles = moles × Avogadro's Number

= 0.118 mol × (6.022 × 10²³ particles/mol)

= 7.11 × 10²² particles

3 0

3 years ago

Which of the following words correctly describes CO2? Select all that apply

MaRussiya [10]

CO2 is a compound, hope this is okay

7 0

3 years ago

1. How many moles are contained in 2.22 x 1024 molecules of calcium fluoride?

Black_prince [1.1K]

Answer:

= 3.7moles

Explanation:

I mole = 6.022 × 10²³ molecules

I molecule = 1 ➗ 6.022 × 10²³ moles

2.22 ×10‘’ 24molecules = (2.22×10‘’ 24) ÷6.022 × 10²³ moles

Number of moles = 2.22/6.022 × 10" 24-23

Number of moles = 0.37 × 10

Number of moles = 3.7moles

I hope this was helpful, please mark as brainliest

3 0

3 years ago

4. Arrange the following substances in order of increasing boiling point: CH3CH2OH, HOCH2CH2OH, CH3CH2Cl , and ClCH2CH2OH A. CH3

Studentka2010 [4]

Answer: Option (B) is the correct answer.

Explanation:

A molecules that will have more number of hydrogen bonding will has highest boiling point because to break the hydrogen bonds high heat needs to be provided.

So, in the molecule $HOCH_{2}CH_{2}OH$ there is presence of two alcoholic groups. Hence, it will have strongest hydrogen bonding as compared to the rest of molecules.

In the molecule $ClCH_{2}CH_{2}OH$ there will be hydrogen bonding and dipole-dipole interactions. Hence, it boiling point will be slightly less than $HOCH_{2}CH_{2}OH$ .

In the molecule $CH_{3}CH_{2}OH$ , there will be only hydrogen bonding. Hence, its boiling point is less than $ClCH_{2}CH_{2}OH$ .

In the molecule $CH_{3}CH_{2}Cl$ , there is no hydrogen bonding but there will be only dipole-dipole interactions. Hence, its boiling point will be the least.

Therefore, we can conclude that increasing order of boiling point will be as follows.

$CH_{3}CH_{2}Cl$ < $CH_{3}CH_{2}OH$ < $ClCH_{2}CH_{2}OH$ < $HOCH_{2}CH_{2}OH$

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