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erma4kov [3.2K]
2 years ago
13

Pls help question is above ​

Chemistry
1 answer:
hodyreva [135]2 years ago
5 0

a. The calories increase by 9:00 whenever the running speed goes up by two. so so if a dog were running at 10 km/h it would be 54 calories burnt

b. they are multiplied by 9

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1 : 6.023x10^23
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(6.023x10^23)X = 4.91x10^22

X = 4.91x10^22/6.023x10^23

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THe answer I belive is B

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