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3 years ago

2NaClO3 ——> 2NaCl + 3O2

Chemistry

1 answer:

Alborosie3 years ago

3 0

Answer:

<h3>1) 208.09 g</h3><h3>2) 7.11 × 10²² particles</h3>

<h2>Explanation:</h2><h3>NUMBER ONE</h3>

<u>Find moles of Known Substance (NaCl)</u>

Moles of NaCl = mass ÷ molar mass

= 114.25 g ÷ 58.44 g/mol

= 1.955 mol

<u>Use Mole Ratio of Known to Unknown (NaCl : NaClO₃) to Determine Moles of Unknown</u>

The mole ratio of NaCl to NaClO₃ is 2 to 2 or simply 1 to 1.

This means that for each mole of NaCl produced the same number of moles of NaClO₃ was decomposed.

∴ since moles of NaCl = 1.955 mol,

then moles of NaClO₃ = 1.955 mol

<u>Find Mass of Unknown </u>

Mass of NaClO₃ = moles × molar mass

= 1.955 mol × 106.44 g/mol

= 208.09 g

<h3>NUMBER TWO</h3>

<u>Determine the Moles of Known (O₂)</u>

moles of O₂ = (volume × density) ÷ molar mass

= (68.30 L × 0.0828 g/L) ÷ 32 g/mol

= 0.177 mol

<u>Use Mole Ratio of Known to Unknown (O₂ : NaClO₃) to Determine Moles of Unknown</u>

Mole ratio of O₂ : NaClO₃ is 3 : 2. Therefore for each mole of oxygen produced, ²/₃ the moles of NaClO₃ is produced.

∴ if moles of O₂ = 0.177 mol

then moles of NaClO₃ = 0.177 mol × ²/₃

= 0.118 mol

<u>Find the Number of Particles of Unknown</u>

Number of particles = moles × Avogadro's Number

= 0.118 mol × (6.022 × 10²³ particles/mol)

= 7.11 × 10²² particles

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Answer: The correct statement is (A new substance is formed and the process can usually NOT be undone.)

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3 years ago

The principal component of mothballs is naphthalene, a compound with a molecular mass of about 130 amu, containing only carbon a

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Answer:

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Molecular formula = C10H8

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When the 3000 mg of naphthalene are burned they produce 10.3 mg of CO2. Knowing the unbalanced equation of the combustion of naphthalene, we have:

CxHy + O2 = CO2 + H2O

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Therefore we have the molecular formula:

(C5H4)2 = C10H8

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