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mojhsa [17]
3 years ago
5

Using the side lengths determine whether the triangle is acute obtuse or right 4 8 5

Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer: acute

Step-by-step explanation:

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The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....
leonid [27]

Answer:

Step-by-step explanation:

Let the solution to

2x^2 + x -1 =0

x^2+ (1/2)x -(1/2)

are a and b

Hence a + b = -(1/2) ( minus the coefficient of x )

ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

2x^2-19x + 44 =0

B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

x^2 +(3/2) x -9/2 = 0

2x^2 + 3x -9 =0.

4 0
3 years ago
F (x) = x^2 reflect across the x-axis translate left 2 units
Morgarella [4.7K]
<span>The correct answer is D) g(x) = -(x + 2)^2. The given formula F(x) = x^2 creates a parabola that is open at the top. To reflect this figure across the x-axis and have it open at the bottom, the y-position of the figure on the coordinate system for every x value, which is F(x) = y = x^2 has to be inverted. This is done by negating y and respectively x^2, so to reflect the figure on the x-axis the formula would now look like this: F(x) = -y = -x^2. To move any parabola two units to the left and thereby have its root be at -2, you would simply subtract -2 from every x-position of the figure in the coordinate system. For an inverted parabola like this one the value to move it on the x-axis has to be added instead and this results in the formula from answer D: g(x) = -(x+2)^2</span>
6 0
3 years ago
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Arte-miy333 [17]
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4 0
3 years ago
Read 2 more answers
5. A map is drawn to a scale of 3:750.
Ainat [17]

Answer:

23.1m

Step-by-step explanation:

we define x to be the actual distance, y to be the distance on map (y=15.4cm)

if the map scale is 3:750, then by definition of scaling, x and y must satisfy:

\frac{y}{x}  =  \frac{3}{750}  =  \frac{1}{150}

we isolate x:

x = 150 \times y = 150 \times 15.4 = 2310cm = 23.1m

7 0
2 years ago
What expression is equivalent to (8 squarded )and -4
kiruha [24]

Answer:

8^{2} + -4   = 64 - 4 =60

Step-by-step explanation:

5 0
3 years ago
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