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Natali [406]
3 years ago
14

I need help.

Mathematics
2 answers:
Mariulka [41]3 years ago
7 0

Answer:

b)On the scatter plot of the data, there are some points above and below the regression line, but no points that fall on the line.

d)The residuals do not appear to follow a pattern.

e)The line is a good fit for the data.

f)The residuals are relatively small compared to the actual data values.

aleksklad [387]3 years ago
6 0

Answer:

b)On the scatter plot of the data, there are some points above and below the regression line, but no points that fall on the line.

c)The line is not a good fit for the data.

f)The residuals are relatively small compared to the actual data values.

Thanks in advanced

Step-by-step explanation:

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During the holiday sale at blooming department store all sweaters are discounted 30% on blockbuster Saturday the store discounts
RSB [31]

Answer: He would pay $62.37 for it on blockbuster Saturday.

Step-by-step explanation:

Since we have given that

Original price of sweater = $99

Discount on blockbuster Saturday = 30%

Additional discount on sweater = 10%

So, According to question,

Net\ Price=Price\times \frac{100-Discount}{100}\\\\\text{As there are 2 successive discounts }\\\\So,\\\\Net\ Price=Price\times \frac{100-D_1}{100}\times\frac{100-D_2}{100}

99\times \frac{100-30}{100}\times \frac{100-10}{100}\\\\=99\times \frac{70}{100}\times \frac{90}{100}\\\\=\$62.37

Hence, he would pay $62.37 for it on blockbuster Saturday.

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2 years ago
Graph this equation y=7/2x-2
Ludmilka [50]
To find the slope and y intercept, use the y=mx+b formula where m is the slope and b is the y intercept<span>.
</span><span>y=mx+b

</span>Pull the values of m and b using the y=mx+b formula<span>.
</span><span>m=7/2,</span>b=−2 where m is the slope and b is the <span>y-intercept</span>

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1.a) Convert 81° into grade.<br>10​
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Step-by-step explanation:

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Select the statement that correctly compares two numbers. (GIVING BRAINLIEST)
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Answer:

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Read 2 more answers
Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter
Vaselesa [24]

We have been given a function f(x)=2x^3+3x^2-336x. We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

f'(x)=2(3)x^{2}+3(2)x^1-336

f'(x)=6x^{2}+6x-336

6x^{2}+6x-336=0

x^{2}+x-56=0

x^{2}+8x-7x-56=0

(x+8)-7(x+8)=0

(x+8)(x-7)=0

x=-8,x=7

So x=-8,7 are critical points and these will divide our function in 3 intervals (-\infty,-8)U(-8,7)U(7,\infty).

Now we will find derivative over each interval as:

f'(x)=(x+8)(x-7)

f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16

Since f'(9)>0, therefore, function is increasing on interval (-\infty,-8).

f'(x)=(x+8)(x-7)

f'(1)=(1+8)(1-7)=(9)(-6)=-54

Since f'(1), therefore, function is decreasing on interval (-8,7).

Let us check for the derivative at x=8.

f'(x)=(x+8)(x-7)

f'(8)=(8+8)(8-7)=(16)(1)=16

Since f'(8)>0, therefore, function is increasing on interval (7,\infty).

(b) Since x=-8,7 are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

f(-8)=2(-8)^3+3(-8)^2-336(-8)

f(-8)=1856

f(7)=2(7)^3+3(7)^2-336(7)

f(7)=-1519

Therefore, (-8,1856) is a local maximum and (7,-1519) is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

f''(x)=6(2)x^{1}+6

f''(x)=12x+6

12x+6=0

12x=-6

\frac{12x}{12}=-\frac{6}{12}

x=-\frac{1}{2}

Therefore, x=-\frac{1}{2} is an inflection point of given function.

3 0
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