At a convention for lawyers it was known that of the 100 present, at least one was honest, yet if you met any two of the lawyers
, you could guarantee that at least one of the two would be crooked. How many honest lawyers were present?
1 answer:
From the given condition, there is only one honest lawyer present.
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The polynomial p(x) can be found by multiplying 'x-3' to every term

Now distribute and you have your answer.
y=x
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Answer:
substituting the given values we get,
3(1-1)+2*2
using bodmas we get
3(0)+2*2
0+2*2
0+4
4
therefore the answer is 4,thank you and mark the answer as brainliest if u find my answer helpful
The answer to your question is most likely A
The answer will be/is 0,1