Question

A cylindrical plastic container with a 6 ft diameter is placed on the bed of a truck to take water to remote plantings. If the container is filled with water to a height of 3.4 feet, what are the gauge pressure and total weight of the water on the bed of the trunk? (ignore the weight of the plastic tank)

Answer 1

Answer:

Weight=6040.8lbf

pressure=1.7445PSI

Exp9lanation:

Hello! To solve this problem use the following steps

1. Find the volume occupied by the water using the equation to calculate the volume of a cylinder

D= diamater=6ft

h=height=3.4ft

V=volume

$V=\frac{\pi }{4} d^2 h=\frac{\pi }{4} (6^2)(3.4)=96.13ft^3$

2. The density of water at normal conditions is 62.4 lbm / ft ^ 3, remember that the mass is the product of the volume by density.

m=v(density)

m=(96.13)(62.4)=5998.68lbm=186.4slug

to find the weight you multiply by gravity (32.2ft / s ^ 2)

W=mg=186.4slug(32.4ft/S^2)=6040.8lbf

3. Manometric pressure is the pressure at the bottom of the tank due exclusively to water, it is equal to the product of gravity (32.2ft / s ^ 2) density and height

$P=(32.2)(62.4)(3.4)=6831.55\frac{ lbm ft}{s^2 ft^2} =1.7445PSI$