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3 years ago

In your own words describe the relationship between pressure, volume and temperature when talking about a gas.

Physics

1 answer:

maxonik [38]3 years ago

7 0

Answer:

The volume of a given gas sample is directly proportional to it's absolute temperature at constant pressure. The volume of a given amount of gas is inversely proportional to its pressure when the temperature is held constant.

Explanation:

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A 13500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the

Mekhanik [1.2K]

Answer

given,

mass of the jet airplane = 13500 kg

Force on the plane = 35700 N due north

force from wind = 15300 N in direction 80.0° south of west.

Force = $35700 \vec{j} N$

force by wind = $15300(-cos \theta \vec{i}-sin \theta \vec{j})$ N

= $15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$ N

net force on the jet airplane(ma)

$m a = 35700 \vec{j} + 15300(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$

$\vec{a} = \dfrac{35700}{13500} \vec{j} + \dfrac{15300}{13500}(-cos 80^0 \vec{i}-sin 80^0 \vec{j})$

$\vec{a} = 2.64\vec{j} -0.197 \vec{i} - 1.116 sin 80^0 \vec{j})$

$\vec{a} = -0.197 \vec{i} + 1.524 \vec{j}$

$a = \sqrt{-0.197^2+1.524^2}$

a = 1.54 m/s²

$\theta = tan^{-1}(\dfrac{-1.524}{0.197})$

$\theta = -82.63^0$

3 0

3 years ago

A terrorist throws a grenade with a 6.00 second fuse off a building 150.0 m high at a speed of 10.0 m/s. If the angle at which t

igomit [66]

Here we have a projectile motion. It is type of motion that is made of a vertical shot and a horizontal shot. This is how we will solve it.

Firste step is to find horizontal and vertical component of a speed.
$v_{0x} =v_{0} * cos \alpha$ \\ v_{0y} = v_{0} * sin \alpha [/tex]

We are given this information:
$v_{0} = 10 m/s \\ h=150m \\ \alpha =-30°$
Angle is negative because it is below the horizontal.

VERTICAL SHOT
Time needed for a grenade to fall to the bottom of a building is given by a formula:
$t= \frac{ v_{0y} }{g} \\ t= \frac{v_{0} * sin \alpha}{g} \\ t= \frac{-10*sin(-30)}{9.81} \\ t=0.51s$
We used negative value for a speed because it is considered that upwards shot has positive value and downwards shot has negative value.

The grenade will not explode before it hits the ground.

HORIZONTAL SHOT
<span>The horizontal distance from the building at which the grenade will land is called range. The formula for a range is given by:
</span> $R= v_{0x} * \sqrt{ \frac{2h}{g} } \\ R=v_{0} * cos \alpha* \sqrt{ \frac{2h}{g} } \\ R=10*cos(-30)* \sqrt{ \frac{2*150}{9.81} } \\ R=47.89m$

The grenade will hit the ground at distance of 47.89m.

7 0

3 years ago

Which type of fitness is not based on performance?

Aneli [31]

Fitness can be measured during the actual performance.
Which means that there are a lot of factors that can affect agility, speed, and coordination beside the physical factors itself. Meanwhile, flexibility solely depends on the physical Factors.

The answer is flexibility .

Hope this helps (:

4 0

3 years ago

How many protons are in an element with an atomic number of 8 and a mass number of 18

Vinil7 [7]

The answer is 8 protons hope this helps.

6 0

4 years ago

Read 2 more answers

A ball is thrown vertically into the air with a initial velocity of 20 m/s. Find the maximum height of the ball and find the amo

REY [17]

Answer:

The maximum height of the ball is 20 m. The ball needs 2 s to reach that height.

Explanation:

The equation that describes the height and velocity of the ball are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height of the ball at time t

y0 = initial height

v0 = initial velocity

t = time

g = acceleration

v = velocity at time t

When the ball is at its maximum height, its velocity is 0, then, using the equation of the velocity, we can calculate the time at which the ball is at its max-height.

v = v0 + g · t

0 = 20 m/s - 9.8 m/s² · t

-20 m/s / -9.8 m/s² = t

t = 2.0 s

Then, the ball reaches its maximum height in 2 s.

Now, we can calculate the max-height obtaining the position at time t = 2.0 s:

y = y0 + v0 · t + 1/2 · g · t²

y = 0 m + 20 m/s · 2 s - 1/2 · 9,8 m/s² · (2 s)²

y = 20 m

8 0

4 years ago