The moon surface is
visible to an observer on earth due to the gravitational force that attracts
the moon to the earth. The more massive the body is, the more the smaller body
is attracted to the larger body. We can only see the side of the moon due to
the speed at which the moon rotates.
im probably wrong but probably increase because if they get closer the static/sparks to cause a reaction
F1x + F2x = Rx
↓
Rx = F1x + F2x
↓
Rx = F1 cos45° + F2
↓
Rx = (50N)(cos45°) + 60N
↓
Rx = 95N
Similarly, if we sum all the y components, we will get the y component of the resultant force:
F1y + F2y = Ry
↓
Ry = F1y + F2y
↓
Ry = F1 sin45° + 0
↓
Ry = F1 sin45°
↓
Ry = (50N)(sin45°)
↓
Ry = 35N
At this point, we know the x and y components of R, which we can use to find the magnitude and direction of R:
Rx = 95N
Ry = 35N
It is (A) for the first one and (B) for the second one.
Please check the attached picture
