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11Alexandr11 [23.1K]
3 years ago
8

Explain why you would make one of the addends a tens number when solving an addition problem

Mathematics
1 answer:
leonid [27]3 years ago
4 0
<span> You refer to a multiple of ten. As a multiple of ten you can just add it to another number easier than a "ones number".</span>
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0.6 = 08

Step-by-step explanation:

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Using the triangle pictured, find the measure of side AB. Round your answer to the nearest tenth. A) 1.6 B) 2.2 C) 2.7 D) 3.3
Yuki888 [10]

Answer:

Option B (AB = 2.2 units).

Step-by-step explanation:

The diagram shows that there are two sides given and one angle is given. Therefore, the sine rule must be used to solve the question. The sine rule can be written as:

sin ABC / AC = sin BAC / BC.

Plugging ABC=72 degrees, AC=2.5, and BC=2.1 in the sine rule gives:

sin 72 / 2.5 = sin BAC / 2.1.

Cross multiplying gives:

sin BAC = (2.1*sin 72)/2.5.

sin BAC = 0.79888747368.

Taking sin inverse on both sides gives:

BAC = arcsin (0.79888747368) = 53.0239949 degrees.

To find AB, first, the angle ACB is required. To find that angle, use the triangular law of angles. All the three angles sum up to 180 degrees. Therefore ACB = 180 - 72 - 53.0239949 = 54.9760051  degrees.

Now applying the Sine Rule to find AB:

sin ACB / AB = sin ABC / AC.

sin (54.9760051) / AB = sin 72 / 2.5.

AB = (2.5*sin (54.9760051))/sin (72) = 2.2 (to the nearest tenth).

Therefore, AB = 2.2 units, i.e. Option B!!!

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What is the quotient?<br><br> x + 1)3x2 − 2x + 7
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Answer:

3x-5

Step-by-step explanation:

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Which ones are like terms?<br> -1 and 4<br> 3x and -6<br> 5x and -1<br> 5x and 4
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two similar triangles, the perimeter of the first is 74cm. and the side lengths of the other are 4.5cm, 6cm and 8cm find the len
Amiraneli [1.4K]

\huge\mathfrak{\underline{Answer:}}

❒ The length of longest side of first Trianlge :

‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ\large\bf{32\:cm}

__________________________________________

\large\bf{\underline{given:}}

  • Two similar triangles
  • Perimeter of first Trianlge is 74 cm
  • Side length of second triangle are 4.5cm , 6cm and 8cm

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf A$}\put(0.5,-0.3){$\bf C$}\put(5.2,-0.3){$\bf B$}\end{picture}

\setlength{\unitlength}{0.75 cm}\begin{picture}(0,1)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){$\bf P$}\put(0.5,-0.3){$\bf R$}\put(5.2,-0.3){$\bf Q$}\end{picture}

__________________________________________

\large\bf{\underline{To \:find :}}

  • The length of longest side of first Trianlge

__________________________________________

\large\bf{\underline{Perimeter\:of\: second\: triangle:}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=sum\:of\:all\:sides}

‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=4.5+6+8}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=18.5}

❒ The ratio between the perimeter of two triangles :

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=\frac{perimeter\:of\:1st\: triangle}{perimeter\:of\:2nd\: triangle}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=\frac{74}{18.5}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=4:1}

❒ The two triangles are similar , therefore the ratio of their sides will also be similar , i.e 4:1

➽ Let the sides of first Trianlge be x , y and z

\large\bf{\underline{Therefore:}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹\frac{x}{4.5}=\frac{4}{1}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹\frac{y}{6}=\frac{4}{1}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹\frac{z}{8}=\frac{4}{1}}

\large\bf{\underline{Hence:}}

❒ Length of first side :

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹\frac{x}{4.5}=\frac{4}{1}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹x=4\times 4.5}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹x=18}

❒ Length of second side :

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹\frac{y}{6}=\frac{4}{1}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹y=4\times 6}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹y=24}

❒ Length of third side :

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹\frac{z}{8}=\frac{4}{1}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹z=4\times 8}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹z=32}

__________________________________________

\large\mathfrak{Length\:of\: largest\:side:}

\huge\bf{=32cm}

5 0
2 years ago
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