Answer: Last option.
Step-by-step explanation:
For this exercise it is important to remember that a Right triangle is a triangle that has an angle that measures 90 degrees.
By definition, given a Right triangle, if you draw an altitutde from the vertex of the angle that measures 90 degrees (The right angle) to the hypotenuse, the measure of that altitude is the geometric mean between the measures of the two segments of the hypotenuse.
In this case, you have the Right triangle 
given in the picture attached.
You can notice that 
goes from the vertex of right angle (
) to the hypotenuse 
. Therefore, it divides the hypotenuse into two segments. These are:
and 
Therefore, is the geometric mean of the segments and .
Answer:
= x^4 -x^3 -4x^2 -3
Step-by-step explanation:
f(x) = x^4 -x^2 +9
g(x) = x^3 +3x^2 +12
We want to find f-g
(f-g) (x) = x^4 -x^2 +9 - (x^3 +3x^2 +12)
Distribute the minus sign
(f-g) (x) = x^4 -x^2 +9 - x^3 -3x^2 -12
= x^4 -x^3 -4x^2 -3
So the rule with multiplying exponents of the same base is to add the exponents together. Applying this rule here would look like this:
In short, your simplified expression is going to be -16x^7y^6.
3.0 NOT SURE IF ITS CORRECT
(a) m∠RQS = (1/2)m∠QPR = 37°
(b) m∠QPR = m(arc QR) = 74° . . . . . an arc has the same measure as its central angle
