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Contact [7]
3 years ago
14

Correctly identify the steps and elements in this bacteriophage plaque assay

Chemistry
2 answers:
zalisa [80]3 years ago
7 0

Answer:

<u>The Bacteriophage:</u>

The bacteriophage act as the parasite for most of the bacterial cells, as they attack the cells and invades its cellular boundaries to injects its DNA into the unicellular organism. The bacteriophage uses the host's resources and grows its number inside the cells body. While, most of the time there genes or strands of DNA lie dormant inside the genome of the bacterial cells, on other occasions the bacterial cell ruptures, and the newly formed phages are released into the environment.

Explanation:

Now there are few steps through which the phage passes and forms a number of its look alike in any space with the optimum amount resources.

  1. <u>Step-</u> In the given diagram we see the mixture of molten top agar, bacterial cells and diluted phage suspension, as the first step in the process for the bacterial cells is to find the right amount resources,
  2. <u>Step-</u> Then to start the process the cell phage mixture in poured on to an agar plate,
  3. <u>Step-</u> The process requires some time duration or tenure to assemble its self and for that reason the mixture is left to solidify,
  4. <u>Step-</u> Incubation allows microbial growth and phage replication,
  5. <u>Step-</u> Phage plaques,
  6. <u>Step-</u> Lawn of host cells

lora16 [44]3 years ago
4 0

Step-1: Mixture of molten top agar, bacterial cells and diluted phage suspension

Step-2: Cell phage mixture in poured on to an agar plate

Step-3: Mixture is left to solidify

Step-4:  Incubation allows microbial growth and phage replication

Step-5: Phage plaques

Step-6: Lawn of host cells

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4 years ago
Describe how the Bohr model explains both of these observations.
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Explanation:

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8 0
3 years ago
The combustion of 40.10 g of a compound which contains only C, H, Cl and O yields 58.57 g of CO2 and 14.98 g of H2O. Another sam
elena-14-01-66 [18.8K]

Answer:

The empirical formula is C4H5ClO2

Explanation:

Step 1: Data given

Mass of the sample = 40.10 grams

Mass of CO2 produced = 58.57 grams

Mass of H2O produced = 14.98 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Atomic mass C= 12.01 g/mol

Atomic mass O = 16.0 g/mol

Atomic mass H = 1.01 g/mol

In experiment 2, mass = 75.00 grams and 22.06 grams is Cl

Step 2: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 58.57 grams / 44.01 g/mol

Moles CO2 = 1.33 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol CO2

For 1.33 moles CO2 we have 1.33 moles C

Step 4: Calculate mass C

Mass C = 1.33 grams * 12.01 g/mol

Mass C = 15.97 grams

Step 5: Calculate moles H2O

Moles H2O= 14.98 grams /18.02 g/mol

Moles H2O = 0.831 moles

Step 6: Calculate moles H

For 1mol H2O we have 2 moles H

For 0.831 moles H2O we have 2*0.831 = 1.662 moles H

Step7: Calculate mass H

Mass H = 1.662 moles * 1.01 g/mol

Mass H = 1.68 grams

Step 8: Calculate mass %

%C = (15.97 grams / 40.10) * 100 %

%C = 39.8 %

%H = (1.68 / 40.10 ) *100%

%H = 4.2 %

%Cl = (22.06 / 75.00 ) * 100%

%Cl = 29.4 %

%O = 100 % - 39.8% - 4.2 % - 29.4 %

%O = 26.6 %

Step 9: Calculate moles in compound

We assume the compound has a mass of 100 grams

Mass C = 39.8 grams

MAss H = 4.2 grams

MAss Cl = 29.4 grams

Mass O = 26.6 grams

Moles C = 39.8 grams / 12.01 g/mol

Moles C = 3.314 moles

Moles H = 4.2 moles / 1.01 g/mol

Moles H = 4.158 moles

Moles Cl =29.4 grams / 35.45 g/mol

Moles Cl = 0.829 moles

Moles O = 26.6 grams / 16.0 g/mol

Moles O = 1.663 moles

Step 10: calculate the mol ratio

We divide by the smallest amount of moles

C: 3.314 moles / 0.829 moles = 4

H: 4.158 moles / 0.829 moles = 5

Cl: 0.829 moles /0.829 moles = 1

O: 1.663 moles / 0.829 moles = 2

This means For each Cl atom we have 4 C atoms, 5 H atoms and 2 O atoms

The empirical formula is C4H5ClO2

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3 years ago
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