All categories

3 years ago

Pls help asap!!!!

Chemistry

1 answer:

AVprozaik [17]3 years ago

3 0

Answer: The pressure of the He is 2.97 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_{N_2}+p_{O_2}+p_{He}.$

Given : $p_{total}$ =total pressure of gases = 6.50 atm

$p_{N_2}$ = partial pressure of Nitrogen = 1.23 atm

$p_{O_2}$ = partial pressure of oxygen = 2.3 atm

$p_{He}$ = partial pressure of Helium = ?

putting in the values we get:

$6.50atm=1.23atm+2.3atm+p_{He}$

$p_{He}=2.97atm$

The pressure of the He is 2.97 atm

You might be interested in

What is the mass of 5 moles of Fe2O?

Elenna [48]

Explanation:

1 miole of Fe2O is 6.22 × 10^-23

5mole of Fe2O = 5×6.22×10^-23

=31.1×10^-23

8 0

3 years ago

K_C204(aq) + _<br> NaOH(aq) →

sveta [45]

Alright cool I have no idea what you’re saying this alien holographic or something u weirdo

7 0

3 years ago

There is 6.4% sales tax on 1,500 television how much tax is owned<br>

Arturiano [62]

Answer:

What you need to know before I explain is how to add percents onto numbers. What I'm saying is what and how to do 6.4% x 1500

1. You can't do a percent and number together, that's impossible

What you can do is convert the percent (6.4%) into a decimal

2. 6.4% is equivalent to 6.4/100, which is equivalent to 0.064

3. Now, you multiply 0.064 x 1500

You will notice, hopefully, that you have a number smaller than 1500, but do not panic, you are on the right track!

4. Using the number you got, add that to 1500, and there's your total!

But, if you want only the tax, keep that small number you started off with!

Explanation:

6 0

3 years ago

What are the Group 1A and Group 7A elements examples of?

Scrat [10]

Alkali metals = Group 1A
Halogens = Group 7A

6 0

4 years ago

Read 2 more answers

A person tries to heat up her bath water by adding 5.0 L of water at 80°C to 60 L of water at 30°C. What is the final temperatur

Ratling [72]

Answer: $T_f=33.85\°C$

Explanation:

Hello,

In this case, we can write the following relationship, explaining that the lost by the hot water is gained by the cold water:

$Q_{hot,W}=-Q_{cold,W}$

Which in terms of mass, specific heat and temperatures, we have:

$m_{hot,W}Cp_{W}(T_f-T_{hot,W})=-m_{cold,W}Cp_{W}(T_f-T_{cold,W})$

Whereas the specific heat of water is cancelled out to obtain the following temperature, considering that the density of water is 1 kg/L:

$T_f=\frac{m_{hot,W}T_{hot,W}+m_{cold,W}T_{cold,W}}{m_{hot,W}+m_{cold,W}}\\\\T_f=\frac{5.0kg*80\°C+60kg*30\°C}{5.0kg+60kg} \\\\T_f=33.85\°C$

Regards.

4 0

3 years ago