All categories

3 years ago

Color corresponds to the ______________ of light waves..

2 answers:

8 0

Color corresponds to the wavelength of light waves.
The shortest light waves are "violet", the longest light waves are "red".

hjlf3 years ago

6 0

The correct answer is

C.wavelength

In fact, the colour of visible light depends on the wavelength of the wave. The visible light spectrum goes approximately from wavelength of 380 nm (corresponding to violet light) to 750 nm (corresponding to red light), and the different colours in between correspond to different wavelengths. For instance, blue light has wavelength of 450-500 nm, while yellow light has wavelength of 570-590 nm.

You might be interested in

If a vector 2ỉ +3j +8k is perpendicular to the<br> vector 4j-4i + ak, then the value of a is

natita [175]

Explanation:

if two vectors are perpendicular to each other then thier dot product is equal to zero so (2i+3j+8k).(-4i+4j+ak)=0 (2)(-4) +(3)(4)+(8)(a) =0 -8+12+8a=0 4+8a=0 8a=-4

$a = \frac{ - 4}{8}$

$a = \frac{ - 1}{2}$

4 0

3 years ago

The force of attraction between two like charged table tennis balls is 2.4 × 10-5 newtons. If the charge on the one is 3.8 × 10-

k0ka [10]

To have a force of 3.8x10-8 the two chaarges must be 0.65m apart.

7 0

4 years ago

Read 2 more answers

A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr

fgiga [73]

Answer:

<em>The balloon is 66.62 m high</em>

Explanation:

<u>Combined Motion </u>

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

$\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}$

The values are

$\displaystyle y_o=15\ m$

$\displaystyle v_o=14\ m/s$

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

$\displaystyle y=0$

$\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0$

Multiplying by 2

$\displaystyle 2y_o+2v_ot-gt^2=0$

Clearing the coefficient of $t^2$

$\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0$

Plugging in the given values, we reach to a second-degree equation

$\displaystyle t^2-2.857t-3.061=0$

The equation has two roots, but we only keep the positive root

$\displaystyle \boxed {t=3.69\ s}$

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

$\displaystyle Y_r=15+V_r.t$

$\displaystyle Y_r=15+14\times3.69$

$\displaystyle \boxed{Y_r=66.62\ m}$

3 0

3 years ago

A uniform cylinder of mass 1.5 kg and radius 0.3 m rolls down a ramp inclined at an angle 0.12 radians to the horizontal. What i

marishachu [46]

Answer:

<h3> different crystals from 6 to the point of the day I am not sure if you are aware of this but I am not sure if you are aware of this but I am not sure if you have any idea of how 3 is going to be able or not 2 3 or even if you have a good day or two to get to know you a 3 of a good place To Go for your own business or business 5 52 you are a great 49,494 548 4.</h3>

6 0

3 years ago

A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci

Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

$\vec v_1=(x_1,y_1)$