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3 years ago

5

You are listening to music in your room and you are asked to turn down the volume of your music. When you turn down the volume w

hat will happen to the sound waves' amplitude?

1 answer:

djyliett [7]3 years ago

6 0

The sound waves will get smaller and smaller till there is no more bc it is off.

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Match the following list of key words with their definitions

Korvikt [17]

Question 1 :

1. VELOCITY

2. SPEED

3. NEWTON

4. MOMENTUM

5. MASS

Question 2

1. FORCE

2. FRICTION

3. GRAVITY

4. ELECTROAGNETIC FORCE

5. ACCELERATION

6 0

1 year ago

Draw an energy chain diagram to show energy transformations for this event:

larisa86 [58]

The energy chain diagram in this case is chemical energy >> energy conversion >> motion (kinetic) energy + thermal energy.

<h3>What is an energy chain diagram?</h3>

An energy chain diagram is a graphic representation indicating the conversion between different types of energies.

Kinetic energy is a type of motion (movement) energy generated by using potential (stored) energy.

Chemical energy (in this case, the fuel of the car) is a type of energy that is stored to perform work.

Learn more about kinetic energy here:

brainly.com/question/25959744

8 0

2 years ago

A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the

Mashutka [201]

Answer:

4v/3

Explanation:

Assume elastic collision by the law of momentum conservation:

$m_1v = m_1v_1 + m_2v_2$

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively

Substitute $m_2 = m_1/2 \& v_1 = v/3$

$m_1v = \frac{m_1v}{3} + \frac{m_1v_2}{2}$

Divide both side by $m_1$ , then multiply by 6 we have

$6v = 2v + 3v_2$

$3v_2 = 4v$

$v_2 = \frac{4v}{3}$

So the final speed of the second car is 4/3 of the first car original speed

5 0

3 years ago

What is the cow's average velocity to reach the apples?

docker41 [41]

Answer:1.). -0.65

2.). 0.65

Explanation:

3 0

2 years ago

You have probably noticed that carrying a person in a pool of water is much easier than carrying a person through air. To unders

Kruka [31]

Answer:

The answer is "0.91238 and 744.8"

Explanation:

In this scenario it is easier to take a person to the water-pool than to transport the people in the air, as the person's strength is increased by water upwards:

$f_b \to m \to mg =person \\\\F_B \ in\ air = v\ & air\ g \\\\$

$=0.076 \times 1.225 \times 9.8 \\\\ =0.91238 \ N\\\\$

$F_B \ in \ water = v \& water \ g \\\\$

$=0.076 \times 1000 \times 9.8\\\\= 744.8 \ N\\$

6 0

2 years ago