because of god we can hear better at night.
C 1.6 amps hipe this helps
Answer:
Magnitude = 3.64 ×
စ = 43.9°
Explanation:
given data
ship to travel = 1.7 ×
kilometers
turn = 70°
travel an additional = 2.7 ×
kilometers
solution
we will consider here
Px = 1.7 ×
Py = 0
Qx =2.7 ×
cos(70)
Qy= 2.7 ×
sin(70)
so that
Hx = Px + Qx ............1
Hx = 2.62 ×
and
Hy = Py + Qy ..........2
Hy = 2.53 ×
so Magnitude = ![\sqrt{((2.62 \times 10^6 )^2+(2.53 \times 10^6)^2)}](https://tex.z-dn.net/?f=%5Csqrt%7B%28%282.62%20%5Ctimes%2010%5E6%20%20%29%5E2%2B%282.53%20%5Ctimes%2010%5E6%29%5E2%29%7D)
Magnitude = 3.64 ×
so direction will be
tan စ = Hy ÷ Hx ......................3
tan စ =
tan စ = 0.9656
စ = 43.9°
<span>its kinetic energy is 7350kJ
</span>
Kinetic energy is given as =
![\frac{1}{2} mv^{2}](https://tex.z-dn.net/?f=%20%20%5Cfrac%7B1%7D%7B2%7D%20mv%5E%7B2%7D%20)
Now, m = 12 gms = 0.012 kg
And, velocity = 35 kilometers/second = 35000 m/sec
Kinetic energy is given as =
![\frac{1}{2} 0.012 kg * 35000*35000 m/[tex] s^{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%200.012%20kg%20%2A%2035000%2A35000%20m%2F%5Btex%5D%20s%5E%7B2%7D%20)
= 6
![10^{-2}](https://tex.z-dn.net/?f=%2010%5E%7B-2%7D%20)
×1225 ×
![10^{6}](https://tex.z-dn.net/?f=%2010%5E%7B6%7D%20)
m/
= 7350 kJ
Answer:
<h2>
<em><u>D. All of the statements describe nuclear power</u></em></h2>
What is <em><u>NUCLEAR</u></em><em><u> </u></em><em><u>POWER</u></em><em><u>?</u></em><em><u> </u></em>
➡️ is the <u>use of nuclear</u> <u>reactions</u> to <u>produce electricity</u>.
➡️ it can be <u>obtained from nuclear</u> <u>fission, nuclear decay and nuclear fusion reactions. </u>
Hope it helps