The diagonals of a rhombus are perpendicular bisectors of each other, and are also angle bisectors. The 4 congruent right triangles the rhombus is cut into by the two diagonals are 30-60-90 degree triangles, the longer leg is √3/2 of the hypotenuse, √3/2 of 10=5√3. so the longer diagonal is twice of 5√3=10√3
The answer to this equation is six.
Answer: 2 = 28 (72+28 = 90)
Step-by-step explanation:
no picture attached, if it is a right angle angle 2 = 28 (72+28 = 90)
