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Rasek [7]
3 years ago
15

PLEAS help if u dog eats 7 over 8 pounds of food in 4 meals how many meals will it take to eat one pound

Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0
I think it would be 6 meals
Tom [10]3 years ago
6 0
6 meals! (That poor dog must be obese now) Don't forget to rate and give me brainliest answer! Then, I can help you with all your problems! ^-^ ~

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Let G be some point on the diagonal line away from point E.

Angle DEG represents angle 1.

We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.

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Extra side notes:

If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.

If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.

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Answer:

\text{A) }68\:\mathrm{cm}

Step-by-step explanation:

The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.

Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.

To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a 90^{\circ}, creating right triangles \triangle TOP and \triangle SOP.

The Pythagorean Theorem states that the following is true for any right triangle:

a^2+b^2=c^2, where c is the hypotenuse, or the longest side, of the triangle

Thus, we have:

10^2+TP^2=26^2,\\TP^2=26^2-10^2,\\TP^2=\sqrt{576},\\TP=24

Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.

What we know:

  • TP=SP=24
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Thus, the perimeter of the quadrilateral PTOS is equal to 24+24+10+10=\boxed{\text{A) }68\:\mathrm{cm}}

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