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irga5000 [103]
3 years ago
14

Find the vertex for this function. f(x)=-2x^2+8x-11​

Mathematics
1 answer:
loris [4]3 years ago
3 0

\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ f(x)=\stackrel{\stackrel{a}{\downarrow }}{-2}x^2\stackrel{\stackrel{b}{\downarrow }}{+8}x\stackrel{\stackrel{c}{\downarrow }}{-11} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{8}{2(-2)}~~,~~-11-\cfrac{8^2}{4(-2)} \right)\implies \left( 2~~,~~-11+\cfrac{64}{8} \right) \\\\\\ (2~~,~~-11+8)\implies (2~~,~~-3)

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PLZ HELP STUCK ON THIS QUESTION 4a + 6b = 24 6a - 12b = -6 Given the equations what is the value of a+b? PLZ HELP WILL MARK BRAI
Paul [167]

Answer:

a + b = 5

Step-by-step explanation:

To solve this system of equations, we can use a strategy called elimination, which is when we get rid of a variable by adding/subtracting two equations.

Firstly, we want to make sure the absolute value of the coefficients that equal.

Lets eliminate b:

4a + 6b = 24

Multiply both sides by 2:

8a + 12b = 48

We also have:

6a - 12b = -6.

Now lets add that with

8a + 12b = 48

-> 6a + 8a + 12b - 12b = 48 -6

-> 14a = 42

-> a = 3

Now that we know a, lets plug it into one of our original equations:

4(3) + 6b = 24

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Finally, add the two values we found:

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3 years ago
If x=2 and y =0 what is the value of x²-y(x-y)-1​
dimulka [17.4K]

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Step-by-step explanation:

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