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fiasKO [112]
3 years ago
7

Jarred wants to buy a go-cart for $1,200. His part-time job pays him $160 a week. He has already saved $400. Which inequality re

presents the minimum number of weeks (w) he needs to work, in order to have enough money to buy the go-cart?
Mathematics
2 answers:
AlladinOne [14]3 years ago
6 0

he would have to work 163 weeks

BigorU [14]3 years ago
6 0
<h2>Hello!</h2>

The answer is:

MinimumNumberOfWeeks\geq5

<h2>Why?</h2>

First, we need to find the money that Jarred needs including the money that he has already saved.

MoneyNeeded=1200-400=800

So, Jarred needs $800.

If he earns $160 a week, we can find the minimum weeks he has to work in order to earn $800 following the next steps:

WeeksToWork=\frac{MoneyNeeded}{WeeklyEarn}=\frac{800}{160}=5

So, if he has to work at least 5 weeks to earn the total amount of money, it can be expressed by the following inequality:

MinimumNumberOfWeeks\geq5

Have a nice day!

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slope = -1/4 intercept = 50

Step-by-step explanation:

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At Sara's new job she spent $11.52, $6.48, $5.99, $14.00, and $9.50 on lunch the first week. In the second week, she spent $4 mo
elena55 [62]
The total amount that Sara spent for her meals during the first week is,
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During the second week, she spent $4 more making her total equal to $51.49. The average is equal to $10.298. The increase in the mean is equal to,
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4 0
3 years ago
Read 2 more answers
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pogonyaev

Answer:

The answer is (0, 2)

Step-by-step explanation:

Ive also had this question and viewed iver it and said it was right this was some time ago but im glad to help :)

6 0
3 years ago
there are 21 marbles in a blue jar. the blue jars has 3 times as many marbles as a red jar. let m be the number of marbles in th
jarptica [38.1K]

Answer:

m=7

Step-by-step explanation:

1 blue jar = 21 marbles

1 blue jar = 3 red jars

Therefor

21 marbles= 3 red jars

(Now let m=1 red jar)

21= 3m

(Then sine we have 3m dived both sides by 3 to isolate the m)

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5 0
3 years ago
Find three consecutive odd integers such that the sum of the smallest and four times the largest is 61. Please list the numbers
Kipish [7]

Answer:

9,11,13

Step-by-step explanation:

Given: sum of the smallest integer and four times the largest integer out of three consecutive odd integers is 61

To list: numbers from least to greatest

Solution:

Let the three consecutive odd integers be x,x+2,x+4.

According to question,

x+4(x+4)=61\\x+4x+16=61\\5x=61-16\\5x=45\\x=9

So, the integers are x=9,x+2=9+2=11,x+4=9+4=13

Numbers from least to the greatest: 9,11,13

7 0
3 years ago
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