1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula 
to find the distance from point 
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: 
.
Answer:
bags of snack = x = 6
bottles of water = y = 5
Step-by-step explanation:
The system of equations can be used to determine how many of each item they bought.
20.00=2.50x+1.00y
11=x+y
how many bags of snack mix did they buy?
Let
bags of snack = x
bottles of water = y
20.00 = 2.50x + 1.00y (1)
11 = x + y (2)
From (2)
x = 11 - y
Substitute x = 11 - y into (1)
20.00 = 2.50x + 1.00y
20.00 = 2.50(11 - y) + 1.00y
20.00 = 27.5 - 2.50y + 1.00y
20.00 - 27.5 = -2.50y + 1.00y
-7.5 = -1.5y
y = -7.5/-1.5
y = 5
Substitute y = 5 into (2)
11 = x + y
11 = x + 5
11 - 5 = x
x = 6
bags of snack = x = 6
bottles of water = y = 5
That is a rational number.
You cant solve but u can simplify which would be 2b=14
